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crimeas [40]
3 years ago
7

With radiocarbon dating, scientists compare an object's carbon-14 levels with _____. the carbon-14 levels of an object from the

same time period carbon-14 levels in the atmosphere the carbon-14 levels in the rock surrounding the object the object's carbon-12 levels
Chemistry
1 answer:
trapecia [35]3 years ago
5 0

Answer:carbon-14 levels in the atmosphere

Explanation:

When carrying out radiocarbon dating, the level of carbon-14 in a sample is compared with the level of carbon 14 in the atmosphere because, objects exchange carbon-14 with the atmosphere.

Comparison of the activities of carbon-14 in the atmosphere and in the sample gives the age of the sample since the half-life of carbon-14 is a constant.

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A 3.82L balloon filled with gas is warmed from 204.9K to 304.8 K.
likoan [24]

Given :

A 3.82L balloon filled with gas is warmed from 204.9K to 304.8 K.

To Find :

The volume of the gas after it is heated.

Solution :

Since, their is no information about pressure in the question statement let us assume that pressure is constant.

Now, we know by ideal gas equation at constant pressure :

\dfrac{V_1}{V_2} = \dfrac{T_1}{T_2}\\\\\dfrac{3.82}{V_2}= \dfrac{204.9}{304.8}\\\\V_2 = \dfrac{304.8}{204.9} \times 3.82\\\\V_2 = 5.68 \ L

Hence, this is the required solution.

3 0
3 years ago
A student is asked to convert measurements from liters to milliliters and from milliliters to liters. His answers are shown in b
kirza4 [7]
The answer is 3.6L=360mL
5 0
3 years ago
Read 2 more answers
What does the wavelength of a wave measure?
Iteru [2.4K]
Wave length measures the width of the wave
6 0
3 years ago
Read 2 more answers
Convert mass to moles for both reactants. (round to 2 significant figures.)
Maslowich

Answer:

Explanation:

Given parameters:

Mass of CuCl₂  = 2.50g

Mass of Al  = 0.50g

Unknown:

Number of moles of CuCl₂ and Al  = ?

Solution:

To solve this problem, we must understand that the number of moles is a fundamental property used in stoichiometry calculations.

         Number of moles  = \frac{mass}{molar mass}

Molar mass of CuCl₂  = 63.6 + 2(35.5) = 134.5g/mole

Molar mass of Al  = 26.98g/mole

          Number of moles of  CuCl₂  = \frac{2.5}{134.5}  = 0.019moles

        Number of moles of Al  = \frac{0.5}{26.98}   = 0.019moles

4 0
3 years ago
Read 2 more answers
Silver bromide (AgBr) has a solubility of 7.07 × 10^-7 mol/L
kirill115 [55]

a. AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)

b.  Ksp AgBr = s²

c. 5 x 10⁻¹³  mol/L

<h3>Further explanation</h3>

Given

solubility AgBr = 7.07 x 10⁻⁷ mol/L

Required

The dissolution reaction

Ksp

The solubility product constant

Solution

a. dissolution reaction of AgBr

AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)

b. Ksp

Ksp AgBr  = [Ag⁺]  [Br⁻]

Ksp AgBr = (s) (s)

Ksp AgBr = s²

c. Ksp AgBr = (7.07 x 10⁻⁷)² = 5 x 10⁻¹³  mol/L

7 0
3 years ago
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