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4 years ago

Was energy made or created

Chemistry

2 answers:

brilliants [131]4 years ago

7 0

Answer:

Energy cannot be created nor destroyed

Explanation:

Law of conservation of energy

svlad2 [7]4 years ago

4 0

Energy cannot be created or destroyed. it can only be transformed from one form to another.

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Consider the following intermediate chemical equations. 2 equations. First: upper C (s) plus one half upper O subscript 2 (g) ri

Dmitrij [34]

The oxygen in the final equation appears as reactant Upper O subscript 2 (g). Thus, option A is correct.

The chemical equations are the representation of the chemical formula involved in the equation as the reactant and the formed product.

<h3>What will be the form of oxygen?</h3>

The given chemical equations are:

$\rm C\;(s)\;+\;\frac{1}{2}\;O_2\;(g)\rightarrow\;CO\;(g)$
$\rm CO\;(g)+\;\frac{1}{2}\;O_2\;(g)\rightarrow\;CO_2\;(g)$

The final chemical equation formed for the formation of Carbon dioxide is the sum of the two equations.

The final equation is achieved by substituting equation 1 in equation 2.

$\rm C\;(s)\;+\;\frac{1}{2}\;O_2\;(g)\;+\;\dfrac{1}{2}\;O_2\;(g)\;\rightarrow\;CO_2\;(g)\\\\ C\;(s)\;+\;O_2\;(g)\;\rightarrow\;CO_2\;(g)$

The oxygen in the final equation appears as reactant Upper O subscript 2 (g). Thus, option A is correct.

Learn more about the final equation, here:

brainly.com/question/2264209

3 0

2 years ago

Read 2 more answers

If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g･°C) that can be heated from 22.5°C to

inysia [295]

Answer:

The correct answer will be "18.25 g".

Explanation:

The given values are:

Specific heat,

C = 0.45 J/g･°C

Heat involved,

q = 801 J

Temperature,

ΔT = 120.0°C-22.5°C

= 97.5°C

As we know,

⇒ $C = \frac{q}{m \Delta T}$

On substituting the given values, we get

⇒ $0.45=\frac{801}{m(97.5)}$

⇒ $m = 18.25 \ g$

3 0

4 years ago

What pattern do you observe in the coefficients of the hydrocarbon (CxHy) and water (H2O)? How do you explain this pattern?

balu736 [363]

The coefficients of the hydrocarbon and water is 61 and it is explained below.

Explanation:

We have to balance the chemical equation that describes the combustion of octane C₈H₁₈. The combustion of octane involves burning this hydrocarbon in the presence of excess oxygen,O 2. Because octane is a hydrocarbon, that is the compound that contains only carbon and hydrogen, the reaction will produce two products carbon dioxide CO 2 and water H 2 O.

The unbalanced chemical equation is

C₈H₁₈ + O₂ → CO₂ + H₂O

To balance this equation, we have 8 present on the reactant side, so multiply the carbon dioxide by 8 to get 8 atoms of carbon on the products side.

C₈H₁₈ + O₂ → 8 CO₂ + H₂O

Now, we have 18 on the reactant side and 2 on the products side, so multiply the water molecule by 9 to get

C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O

8 * 2 atoms O + 9 *1 atoms O = 25 atoms O

By adding fractional coefficient to O₂ we get

C₈H₁₈ + $\frac{25}{2}$ O₂ → 8 CO₂ + 9 H₂O

Multiply all the coefficients by 2 we get,

2C₈H₁₈ + ( $\frac{25}{2}$ * 2) O₂ → 8 * 2 CO₂ + 9* 2 H₂O

The balance equation is

2C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

Add the coefficients to get their sum

= 2 +25 + 16 +18 = 61

Thus, The coefficients of the hydrocarbon and water is 61

6 0

3 years ago

Calcium hydride reacts with water to form hydrogen gas and calcium hydroxide. How many grams of calcium hydride are needed to ge

4vir4ik [10]

The Equation is CaH2(s)+2H2O(l)-->Ca(OH)2(aq)+2H2(g)

so,

moles of H2 generated = PV / RT

R = 62.363 L Torr K−1 mol−1

number of moles = 814 * 53.5 / 62.363 * 293

= 2.38 moles

looking at the equation these came from 2.38 /2 moles of CaH2 or 1.19 moles

Molar mass of CaH2 is 42.0943 g/mol

so mass of CaH2 = 1.19 X 42.1 = 50.01g

3 0

3 years ago

An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about 4.4x 10 m/s Calculate the

otez555 [7]

The question is incomplete, here is the complete question:

An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about $4.4\times 10^6m/s$ . Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of helium. Write your answer as a percentage of the average speed, and round it to 2 significant digits

<u>Answer:</u> The percentage of average speed is 41 %

<u>Explanation:</u>

We are given:

Radius of helium atom = 31 pm = $31\times 10^{-12}m$ (Conversion factor: $1m=10^{12}pm$ )

So, diameter of helium atom = $(2\times r)=(2\times 31\times 10^{-12})=64\times 10^{-12}m$

The diameter of the atom will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

$\Delta x.\Delta p=\frac{h}{2\pi}$

where,

$\Delta x$ = uncertainty in position = d = $64\times 10^{-12}m$

$\Delta p$ = uncertainty in momentum = $m\Delta v$

m = mass of electron = $9.1095\times 10^{-31}kg$

h = Planck's constant = $6.627\times 10^{-34}kgm^2/s^2$

Putting values in above equation, we get:

$64\times 10^{-12}m\times 9.1095\times 10^{-31}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 64\times 10^{-12}m\times 9.1095\times 10^{-31}kg}=1.81\times 10^6m/s$

To calculate the percentage of average speed, we use the equation:

$\text{Percentage of the average speed}=\frac{\text{Uncertainty in velocity}}{\text{Average orbital speed}}\times 100$

We are given:

Average orbital speed = $4.4\times 10^6m/s$

Putting values in above equation, we get:

$\text{Percentage of the average speed}=\frac{1.81\times 10^6m/s}{4.4\times 10^6m/s}\times 100\\\\\text{Percentage of the average speed}=41.\%$

Hence, the percentage of average speed is 41 %

3 0

4 years ago