Question

A room has dimensions 6.8m x 9.2m. Steven wants to paint the walls of the room. A large tin of paint covers 20m^2 and cost £11.75. Ignoring windows and doors, and allowing for 2 coats of paint, how much will it cost Steven to paint the room.

Answer 1

Answer:

Total cost to paint the room = £73.51

Step-by-step explanation:

Given:

Dimensions of the room = 6.8 m $\times$ 9.2 m

Cost of tin of paint = £11.75

A tin of paint covers an area = 20 $m^2$

To find the cost of painting the room with two coats of paint.

Solution:

Area of the room = $length\times width=6.8\ m\times 9.2\ m= 62.56\ m^2$

We will use unitary method to find the amount of paint required for the room.

If $20\ m^2$ of area is covered by 1 tin of paint.

For $1\ m^2$ of area, amount of paint required = $\frac{1}{20}$ of a tin

Then, for $62.56\ m^2$ amount of paint required = $\frac{62.56}{20}=3.128$ tins of paint.

For double coats twice paint must be required.

So, total amount of paint required for painting the room with two coats of paint = $3.128\times 2=6.256$ tins of paints.

Using unitary method to find total cost.

If 1 tin of paint costs = £11.75

6.256 tins of paint will cost = $6.256\times \£11.75=\£73.508\approx\£73.51$

Total cost to paint the room = £73.51