Answer:
the elements towards the bottom left corner
Answer:
low freezing point. high vapour pressure.
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Answer:
a) p = 25.8 10⁻¹² C m
, b) The direction of the dipole moment is directed from the negative to the positive charge, c) E = 4.65 10² N/C
Explanation:
a) The dipole moment is
p = 2qa
p = 2 4.30 10⁻⁹ 3.00 10⁻³
p = 25.8 10⁻¹² C m
b) The direction of the dipole moment is directed from the negative to the positive charge, that is, in the opposite direction to the electric field.
c) The torque is
τ = p x E
τ = p E sin θ
E = τ / p sin θ
E = 7.20 10⁻⁹ /(25.8 10⁻¹² sin 36.9)
E = 4.65 10² N/C
We calculate
τ = 15.49 10⁻¹² 4.7 10²
τ = 7.28 10⁻⁹ N m
Answer:
B. Tuogh
D. Ampletude
Explanation:
Sorry yan lang ang alam ko
Hope its help to you
Answer:
The speed of the raft is 1.05 m/s
Explanation:
The equation for the position of the stone is as follows:
y = y0 + v0 · t + 1/2 · g · t²
Where:
y = height of the stone at time t
y0 = initial height
v0 = initial speed
t = time
g = acceleration due to gravity
The equation for the position of the raft is as follows:
x = x0 + v · t
Where:
x = position of the raft at time t
x0 = initial position
v = velocity
t = time
To find the speed of the raft, we have to know how much time the raft traveled until the stone reached the river. For that, we can calculate the time of free fall of the stone:
y = y0 + v0 · t + 1/2 · g · t² (v0=0 because the stone is dropped from rest)
If we place the origin of the frame of reference at the river below the bridge:
0 m = 95.6 m - 9.8 m/s² · t²
-95.6 m / -9,8 m/s² = t²
t = 3.12 s
We know that the raft traveled (4.84 m - 1.56 m) 3.28 m in that time, then the velocity of the raft will be:
x/t = v
3.28 m / 3.12 s = v
v = 1.05 m/s
