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allochka39001 [22]
3 years ago
11

In one eight-hour workday, a forklift operator at a particular distribution warehouse lifts a total of 100,000 N of boxes. Each

box must be lifted to a height of 1.5 m and carried an average of 10 m to the shipping dock. What is the net work done against gravity?
Physics
1 answer:
german3 years ago
3 0

Answer:

150000 J

Explanation:

Only the work that is used to lift the boxes up by 1.5 m is counted against gravity. The work that is used to move 10m to the dock is not.

This work done to lift up by 1.5m is the product of force lifted F = 100 000 N and the vertical distance in height h = 1.5m

W = F*h = 100000*1.5 = 150000 J

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(a) the principle of aerodynamic convergence

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(c) Conservation of angular momentum

(d) Conservation of kinetic energy

(e) None of these

Conservation of angular momentum

Answer: Option C.

<u>Explanation:</u>

The law of conservation of angular momentum expresses that when no outer torque follows up on an article, no difference in precise force will happen.

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4 years ago
If a 42kg rolling object slows from 11.5 m/s to 3.33 m/s how much work does friction do?
lara31 [8.8K]

Explanation:

work done by friction = 1/2 x 42 x ( 3.33^2 - 11.5^2)

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= 21 ( - 121.17 )

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3 years ago
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I am?

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Read 2 more answers
A person pushes a 50kg box to the right with 100N of force at a constant velocity of 5m/s. Calculate the coefficient of friction
Anna11 [10]
The weight of the box is 50x9.8 = 490 N. The force of friction is 100N. F= μΝ so coefficient = 100/490 = 0.20
8 0
3 years ago
A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu
Bumek [7]

Answer:

a) v1 = 5.52m/s

b) v2 = -1.52m/s

c) v3 = 4.62m/s

d) vt = 3.85m/s

Explanation:

The velocity of the football wide receiver is his displacement per unit time.

Velocity v = (displacement d)/time t

v = d/t .....1

For each of the cases, equation 1 would be used to calculate the velocity.

a) v1 = d1/t1

d1= 16m

t1 = 2.9s

v1 = 16m/2.9s

v1 = 5.52m/s

b) v2 = d2/t2

d2 = -2.5m

t2 = 1.65s

v2 = -2.5/1.65

v2 = -1.52m/s

c) v3 = d3/t3

d3 = 24m

t3 = 5.2s

v3 = 24/5.2

v3 = 4.62m/s

d) vt = dt/tt

dt = 16m - 2.5m + 24m = 37.5m

tt = 2.9 + 1.65 + 5.2 = 9.75s

vt = 37.5/9.75

vt = 3.85m/s

5 0
4 years ago
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