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Lera25 [3.4K]
4 years ago
12

Suppose the wavelength of the light is 550 nm . How much farther is it from the dot on the screen in the center of fringe E to t

he left slit than it is from the dot to the right slit

Physics
1 answer:
Bogdan [553]4 years ago
3 0

Complete question:

Suppose the wavelength of the light is 550 nm . How much farther is it from the dot on the screen in the center of fringe E to the left slit than it is from the dot to the right slit? Fringe C is the central maximum.

Check the image uploaded.

Answer:

The difference is 1100 nm

Explanation:

A bright fringe creates constructive interference, the wavelength is always in a multiple form.

At center fringe, the difference is (550 nm)(0) = 0

For the first maximum, the difference is (550 nm)(1) = 550 nm

For the second maximum, the difference = (550 nm)(2) = 1100 nm

Thus, for nth maxima, the difference is (550 nm)(n)

From the image uploaded, C is located on the second maximum, therefore the difference is given as  (550 nm)(2) = 1100 nm

Therefore, the dot on the screen in the center of fringe E to the left slit is 1100 nm

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3 0
3 years ago
  The diagram shows a tray of marbles being shaken from side to side.  As this happens some of the marbles jump out of the tray.
irakobra [83]
The marbles that are 'more energetic' fall out of the tray, in the same way particles have enough energy to escape and turn into a gas.
8 0
3 years ago
Light rays in a material with index of refrection 1.35 1.35 can undergo total internal reflection when they strike the interface
nekit [7.7K]

Answer:

1.30

Explanation:

To calculate the critical angle we have ti use the formula:

sin\theta_c=\frac{n_2}{n_1}

where theta_c is the critical angle, n1 is the index of refraction of the material where the light is totally reflected, and n2 is the refractive index of the other material.

By taking n_2 and replacing we obtain:

n_2=n_1sin\theta_c=(1.35)sin75.1\°=1.30

hope this helps!!

6 0
3 years ago
A house is lifted from its foundations onto a truck for relocation. The house is pulled upward by a net force of 2850 N. This fo
Gwar [14]

Answer:

m = 95000 kg

Explanation:

Given that,

Net force acting on the house, F = 2850 N

Initial speed, u = 0

Final speed, v = 15 cm/s = 0.15 m/s

We need to find the mass of the house. Let the mass be m. We know that the net force is given by :

F = ma

Where

a is the acceleration of the house.

So,

F=m\dfrac{v-u}{t}\\\\m=\dfrac{Ft}{(v-u)}\\\\m=\dfrac{2850\times 5}{(0.15-0)}\\\\m=95000\ kg

So, the mass of the house is equal to 95000 kg.

3 0
3 years ago
The magnitude of the magnetic flux through the surface of a circular plate is 6.80 10-5 T · m2 when it is placed in a region of
PIT_PIT [208]

Answer:

B = 4.1*10^-3 T = 4.1mT

Explanation:

In order to calculate the strength of the magnetic field, you use the following formula for the magnetic flux trough a surface:

\Phi_B=S\cdot B=SBcos\alpha        (1)

ФB: magnetic flux trough the circular surface = 6.80*10^-5 T.m^2

S: surface area of the circular plate = π.r^2

r: radius of the circular plate = 8.50cm = 0.085m

B: magnitude of the magnetic field = ?

α: angle between the direction of the magnetic field and the normal to the surface area of the circular plate = 43.0°

You solve the equation (1) for B, and replace the values of the other parameters:

B=\frac{\Phi_B}{Scos\alpha}=\frac{6.80*10^{-5}T.m^2}{(\pi (0.085m)^2)cos(43.0\°)}\\\\B=4.1*10^{-3}T=4.1mT

The strength of the magntetic field is 4.1mT

4 0
3 years ago
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