Suppose the wavelength of the light is 550 nm . How much farther is it from the dot on the screen in the center of fringe E to t
he left slit than it is from the dot to the right slit
1 answer:
Complete question:
Suppose the wavelength of the light is 550 nm . How much farther is it from the dot on the screen in the center of fringe E to the left slit than it is from the dot to the right slit? Fringe C is the central maximum.
Check the image uploaded.
Answer:
The difference is 1100 nm
Explanation:
A bright fringe creates constructive interference, the wavelength is always in a multiple form.
At center fringe, the difference is (550 nm)(0) = 0
For the first maximum, the difference is (550 nm)(1) = 550 nm
For the second maximum, the difference = (550 nm)(2) = 1100 nm
Thus, for nth maxima, the difference is (550 nm)(n)
From the image uploaded, C is located on the second maximum, therefore the difference is given as (550 nm)(2) = 1100 nm
Therefore, the dot on the screen in the center of fringe E to the left slit is 1100 nm
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Incomplete question as the angle between the force is not given I assumed angle of 55°.The complete question is here
Two forces, a vertical force of 22 lb and another of 16 lb, act on the same object. The angle between these forces is 55°. Find the magnitude and direction angle from the positive x-axis of the resultant force that acts on the object. (Round to one decimal places.)
Answer:
Resultant Force=33.8 lb
Angle=67.2°
Explanation:
Given data
Fa=22 lb
Fb=16 lb
Θ=55⁰
To find
(i) Resultant Force F
(ii)Angle α
Solution
First we need to represent the forces in vector form
Total Force
The Resultant Force is given as
For(ii) angle
We can find the angle bu using tanα=y/x
So