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kirza4 [7]
3 years ago
12

A particle moves along a straight line. Its position at any instant is given by x = 32t− 38t^3/3 where x is in metre and t in se

cond. Find the acceleration of the particle at the instant when particle is at rest.
Physics
1 answer:
Rudik [331]3 years ago
4 0

Answer:

The acceleration of the object is -69.78 m/s²

Explanation:

Given;

postion of the particle:

x = 32t - 38\frac{t^3}{3} \\\\

The velocity of the particle is calculated as the change in the position of the  particle with time;

v = \frac{dx}{dt} = 32 - 38t^2\\\\when \ the \ particle \ is \ at \ rest, \ v = 0\\\\32-38t^2 = 0\\\\38t^2 = 32\\\\t^2 = \frac{32}{38} \\\\t = \sqrt{\frac{32}{38} } \\\\t = 0.918 \ s

Acceleration is the change in velocity with time;

a = \frac{dv}{dt} = -76t\\\\recall , \ t = 0.918 \ s\\\\a = -76(0.918)\\\\a = -69.78 \ m/s^2

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<em><u>Given</u></em><em> </em> :

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now, we know

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\frac{1}{f}  =  \frac{1}{v}  +  \frac{1}{u}

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\frac{1}{ - 16}  =  \frac{1}{ - 36}  +  \frac{1}{v}

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\frac{1}{v}  =  \frac{ - 1}{16}  -  \frac{ - 1}{36}

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\frac{1}{v}  =  \frac{ - 9 - ( - 4)}{144}

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8 0
3 years ago
I AN TIMED, HURRY!!
kramer

Answer:

C)0.59 N

Explanation:

By the Achemides principle we know that the buoyancy force on an object which is immersed in a incompressible fluid at rest is equal to the weight of the fluid displaced. So all we have to do is to find the mass of 60ml.

Density = mass / volume

Mass = density × volume

= 1 g/cm³× 60 cm³

{ as 1ml=1cm³}

= 60 g

So force equals to,

Force = weight = mass × gravitational acceleration

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3 years ago
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= 1691.58 N/3

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