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GarryVolchara [31]
3 years ago
12

A ping pong ball with a mass of 2.20 grams rolls along a frictionless table with a velocity of 0.850 m/s. what is the momentum o

f the ping pong ball?1.87 g m/s2.59 g m/s1.59 g m/s3.04 g m/s
Chemistry
2 answers:
snow_lady [41]3 years ago
8 0

<u>Answer:</u> The momentum of the ball is 1.87 g m/s.

<u>Explanation:</u>

Momentum of an object is defined as the product of mass of the object and the velocity of the object. Mathematically,

p=mv

where,

p = momentum of the ball = ? g m/s

m = mass of the ball = 2.20 grams

v = velocity of the ball = 0.850 m/s

Putting values in above equation, we get:

p=2.20g\times 0.850m/s=1.87gm/s

Hence, the momentum of the ball is 1.87 g m/s.

Nataly_w [17]3 years ago
6 0
1.87 should be your answer 
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How many grams of carbon are contained in 2.25 g of potassium carbonate, K2CO3
romanna [79]

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

<h3>Molecular mass of potassium carbonate</h3>

The molecular mass of potassium carbonate, K₂CO₃ is calculated as follows;

M = K₂CO₃

M = (39 x 2) + (12) + (16 x 3)

M = 138 g

mass of carbon in potassium carbonate, K₂CO₃ is = 12 g

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is calculated as follows;

138 g ------------ 12 g of carbon

2.25 g ------------ ?

= (2.25 x 12) / 138

= 0.196 g

Thus, the mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

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2 years ago
What aspect of metallic bonding is responsible for malleability ductility and conductivity of metals?
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One of the commercial uses of sulfuric acid is the production of calcium sulfate and phosphoric acid. If 26.8 g of Ca₃(PO₄)₂ rea
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Answer:

The percent yield reaction is 64.3%

Explanation:

This is the ballanced reaction

Ca₃(PO₄)₂ (s) + 3H₂SO₄ (aq) → 2H₃PO₄ (aq) + 3CaSO₄ (aq)

Let's determine the moles of our reactants:

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1 mol of phosphate reacts with 3 mol of sulfuric so

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I have 0.554 of sulfuric, so this is the reactant in excess.

The limiting reagent is the Phosphate.

1 mol of PO₄⁻³ produces 2 mol of phosphoric

0.0864 of PO₄⁻³ will produce the double amount (0.0864 .2) = 0.173 moles

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Percent yield = (Produced / Theoretical) .100

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