From the information in the question, the E° and E for the cell is 0.00 V and 0.12 V.
Using the Nernst equation;
Ecell = E°cell - 0.0592/n log Q
We know that E°cell = 0.00 V since the anode and cathode are both made up of cadmium.
Substituting the given values into the Nernst equation;
Ecell = 0.00 V - 0.0592/2 log (1.0 × 10-5 M/0.100 M)
Ecell = 0.00 V - 0.0296 log(1 × 10^-4)
Ecell = 0.12 V
Learn more: brainly.com/question/8646601
Answer:
C
Explanation:
A fuel cell uses both hydrogen and oxygen as fuels. At the cathode oxygen is reduced to water according to the equation
O2+4H^+ +4e ------>2H2O
And hydrogen is oxidized at the anode:
2H2------>4H^+ +4e
Fuel cells produce only water as a by product hence they are environment friendly
5-Methyl-5-ethyldecane should be the answer .
Two things
Ferrous Ammonium Sulfate is a pale green or blue-green powder or sand-like solid. It is used in photography, analytical chemistry, and Iron-plating baths.
An FAS-DPD titration is as simple as a test for total alkalinity or calcium hardness. A buffered DPD indicator powder is added to a water sample and reacts with chlorine to produce the pink color characteristic of the standard DPD test.
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