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Elza [17]
3 years ago
13

How many grams of oxygen are required to react completely with 3.6L of hydrogen at

Chemistry
1 answer:
Paladinen [302]3 years ago
7 0
the number of moles of oxygen required are 0.08 mol. The volume of oxygen that is required to react can be calculated by the formula shown below. Substitute the values in equation (II). Hence, the volume of oxygen required to react with 3.6 L hydrogen is 1.8L . I hope this helps if not I’m sorry
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what volume of ethylene gas at 293K and 102kPa must be compressed to yield 295m3 of ethylene gas at 808kPa and 585K​
luda_lava [24]
<h3>Answer:</h3>

1170.43 m³

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial pressure, P1 as 808 kPa
  • Initial temperature, T1 as 585 K
  • Initial volume, V1 as 295 m³
  • New pressure, P2 as 102 kPa
  • New temperature, T2 as 293 K

We are required to find the new volume;

  • We are going to use the combined gas law
  • According to the gas law;  \frac{P1V1}{T1}=\frac{P2V2}{T2}
  • Thus, rearranging the formula;

V2=\frac{P1V1T2}{P2T1}

V2=\frac{(808 kPa)(295)(293K)}{(102 kPa)(585K)}

V2=1170.43

Therefore, the volume is 1170.43 m³

6 0
3 years ago
Calculate the concentration of clo2− at equilibrium if the initial concentration of hclo2 is 2. 25×10^−2 m.
jek_recluse [69]

The concentration of ClO₂⁻ at equilibrium if the initial concentration of  HClO₂ is 0.0654.

<h3>What is concentration?</h3>

The concentration of any substance is the quantity of that substance in per square of the space or container.

The reaction is

HClO₂ + H₂O <=> H₃O⁺ + ClO₂⁻

The pH is 0.454 M

Ka = [H₃O⁺][ClO₂⁻ ] / [HClO₂]

2. 25 × 10⁻² m = [x][x] / 0.454-x]

2 + 0.011 - 0.004994 = 0

solve the quadratic equation

x = 0.0654 = [H3O+] = [ClO2-]

pH = -log (H3O+)

pH = -log(0.0654)

pH = 1.2

equilibrium concentrations of

[HClO2] = 0.454 -x = 0.454 -0.0654 = 0.3886 M

[ClO2- ] = x = 0.0654

Thus, the equilibrium concentrations  is 0.0654.

To learn more about concentration, refer to the link:

brainly.com/question/16645766

#SPJ4

6 0
1 year ago
Helppppp meeeeeeeeeeeeeeeeeeeeeeeeeeeee ill mark brainlist
sergey [27]
Grasshopper population will increase since they have less predators
3 0
3 years ago
Read 2 more answers
2.0 L of oxygen gas and 8.0 L of nitrogen gas at STP are mixed together. The gaseous mixture is compressed to occupy 2.0 L at 29
otez555 [7]

Answer:

5.5 atm

Explanation:

Step 1: Calculate the moles in 2.0 L of oxygen at STP

At STP, 1 mole of an ideal gas occupies 22.4 L.

2.0 L × 1 mol/22.4 L = 0.089 mol

Step 2: Calculate the moles in 8.0 L of nitrogen at STP

At STP, 1 mole of an ideal gas occupies 22.4 L.

8.0 L × 1 mol/22.4 L = 0.36 mol

Step 3: Calculate the total number of moles of the mixture

n = 0.089 mol + 0.36 mol = 0.45 mol

Step 4: Calculate the pressure exerted by the mixture

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T / V

P = 0.45 mol × (0.0821 atm.L/mol.K) × 298 K / 2.0 L = 5.5 atm

3 0
3 years ago
After a covalent bond has stabilized an atom, the atom will have
Dafna1 [17]

<em>Answer:</em>

  • The atom have a full valence electron shell.

<em>Explanation:</em>

  • My question is that why covalent bonds take place?

Every atoms tends to from bond with another atoms in order to get nearest electronic configuration of nobel gases. They become stable when their valence shell become complete. So when covelant bond forms between atoms, share electrons to each other and stabilize themselves.

5 0
3 years ago
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