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3 years ago

How many grams of oxygen are required to react completely with 3.6L of hydrogen at

1 answer:

7 0

the number of moles of oxygen required are 0.08 mol. The volume of oxygen that is required to react can be calculated by the formula shown below. Substitute the values in equation (II). Hence, the volume of oxygen required to react with 3.6 L hydrogen is 1.8L . I hope this helps if not I’m sorry

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What is gold atomic number

Korolek [52]

Answer:

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3 years ago

A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction t

andreev551 [17]

Answer: The volume of the sample after the reaction takes place is 29.25 L.

Explanation:

The given reaction equation is as follows.

$OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)$

So, moles of product formed are calculated as follows.

$\frac{3}{2} \times 0.17 mol \\= 0.255 mol$

Hence, the given data is as follows.

$n_{1}$ = 0.17 mol, $n_{2}$ = 0.255 mol

$V_{1}$ = 19.5 L, $V_{2} = ?$

As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L$

Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

8 0

3 years ago

Please!!!!!!!!!!!!!!!!!!!!!!!

maria [59]

Answer:

yesir

Explanation:

yesir yesir yesssirrrr

3 0

3 years ago

Given 7.40 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100

Dafna11 [192]

On complete conversion (100% yield) 9.75 g of ethyl butyrate will be produced. Below is the solution.....

4 0

3 years ago

Lysine is an amino acid that is an essential part of nutrition but which is not synthesized by the human body. What is the molar

nata0808 [166]

Answer:

The molar mass of lysine using the ideal gas equation for this problem is 146.25 g/mole.

Explanation:

The ideal gas equation PV = nRT, was derived from the ABC laws (Avogadros, Boyles and Charles laws). We need to obtain the value for the number of moles n.

The parameters of this equation are:

P = 1.918 atm

V = 750.0mL = 0.75L

n = ?

R = 0.0821

T = 25 degree celcius = 25 + 273 = 298 degree kelvin.

From this formular, n = (PV)/(RT)

n = (1.918 X 0.75)/(0.0821 X 298 )

n = 0.0588

n, no of mole = mass/molar mass

0.0588 = 8.6/MM

MM = 8.6/0.0588

MM = 146.25g/mole.

4 0

3 years ago

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