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Aneli [31]
3 years ago
14

Indicate whether each of the statements below is true or false. Match the words in the left column to the appropriate blanks in

the sentences on the right. Make certain each sentence is complete before submitting your answer. ResetHelp False True blank: C B r 4 has a higher boiling point than C C l 4.: CBr4 has a higher boiling point than CCl4. blank: C B r 4 has weaker intermolecular forces than C C l 4.: CBr4 has weaker intermolecular forces than CCl4. blank: C B r 4 has a higher vapor pressure at the same temperature than C C l 4.: CBr4 has a higher vapor pressure at the same temperature than CCl4. blank: C B r 4 is more volatile than C C l 4.: CBr4 is more volatile than CCl4.
Chemistry
1 answer:
otez555 [7]3 years ago
5 0

Answer:

1) ) CBr₄ has a higher boiling point than CCl₄: True

2 CBr₄ has weaker intermolecular forces than CCl₄: False

3) CBr₄ has a higher vapor pressure at the same temperature than CCl₄: False

4) CBr₄ is more volatile than CCl₄: False

Explanation:

1) ) CBr₄ has a higher boiling point than CCl₄: True :

Due to higher molecular weight CBr₄ has more london disperion forces thus making the intermolecular interactions stronger and thus it need more temperature to boil it off.

2 CBr₄ has weaker intermolecular forces than CCl₄: False

Due to higher molecular weight CBr₄ has more london disperion forces thus making the intermolecular interactions stronger.

3) CBr₄ has a higher vapor pressure at the same temperature than CCl₄: False

Due to higher molecular weight CBr₄ has more london disperion forces thus making the intermolecular interactions stronger. Thus the vapor pressure of it will be less than CCl₄ at the same temperature.

4) CBr₄ is more volatile than CCl₄: False

Due to higher molecular weight CBr₄ has more london disperion forces thus making the intermolecular interactions stronger. Thus CCl₄ is more volatile.

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What does the roman numeral stand for in copper(1) oxide should it not be copper(II) oxide
photoshop1234 [79]

Answer:

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

Explanation:

Roman numeral is used to indicate the oxidation number of an element in a compound.

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

This can be seen from the following illustration:

copper(I) oxide => Cu₂O

Oxidation number of O = –2

Oxidation number of Cu₂O = 0

Oxidation number of Cu =?

Cu₂O = 0

2Cu + O = 0

2Cu – 2 = 0

Collect like terms

2Cu = 0 + 2

2Cu = 2

Divide both side by 2

Cu = 2/2

Cu = 1

Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.

For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:

copper(II) oxide, CuO => CuO

Oxidation number of O = –2

Oxidation number of CuO = 0

Oxidation number of Cu =?

CuO = 0

Cu + O = 0

Cu – 2 = 0

Collect like terms

Cu = 0 + 2

Cu = 2

Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.

From the above illustrations,

We can see that the roman numeral in both copper(I) oxide, Cu₂O and copper(II) oxide, CuO are different because the oxidation number of Cu in both cases are different.

3 0
3 years ago
Which is the iupac name for no?
pshichka [43]
The IUPAC name of NO is nitric oxide. It is one of the many oxides of nitrogen. It is a colorless gas under standard temperature and pressure. It found great application in the combustion of fossil fuels in power plants. This substance is produced naturally by lightning.
7 0
3 years ago
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How many atoms of iodine are needed to react with one atom of magnesium?
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Answer:

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Explanation:

4 0
3 years ago
How many mols of chlorine are in 120g of chlorine gas
xz_007 [3.2K]

Answer:

Number of moles of chlorine = 3.38 mol

Explanation:

Given data:

Mass of chlorine = 120 g

Moles of chlorine = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of chlorine = 35.5 g/mol

Now we will put the values in formula.

Number of moles = 120 g/ 35.5 g/mol

Number of moles = 3.38 mol

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Explain the reaction of non-metals with oxygen
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