Answer:
obviously 2 hours cuz 850/425
Explanation:
Im pretty sure the answer would be A
Answer:
True
Explanation:
This is true statement because in DC circuit there is only resistance which comes into play of opposition of current.
In DC circuit there is no role of frequency in if there is no frequency then there will no inductive reactance and no capacitive reactance to oppose the current flow
So in DC circuit only resistance is responsible to oppose the flow of current
So this is a true statement
Quasi frequency = 4√6
Quasi period = π√6/12
t ≈ 0.4045
<u>Explanation:</u>
Given:
Mass, m = 20g
τ = 400 dyn.s/cm
k = 3920
u(0) = 2
u'(0) = 0
General differential equation:
mu" + τu' + ku = 0
Replacing the variables with the known value:
20u" + 400u' + 3920u = 0
Divide each side by 20
u" + 20u' + 196u = 0
Determining the characteristic equation by replacing y" with r², y' with r and y with 1 in the differential equation.
r² + 20r + 196 = 0
Determining the roots:
r = -10 ± 4√6i
The general solution for two complex roots are:
y = c₁ eᵃt cosbt + c₂ eᵃt sinbt
with a the real part of the roots and b be the imaginary part of the roots.
Since, a = -10 and b = 4√6
u(t) = c₁e⁻¹⁰^t cos 4√6t + c₂e⁻¹⁰^t sin 4√6t
u(0) = 2
u'(0) = 0
(b)
Quasi frequency:
μ =
(c)
Quasi period:
T = 2π / μ
(d)
|u(t)| < 0.05 cm
u(t) = |2e⁻¹⁰^t cos 4√6t + 5√6/6 e⁻¹⁰^t sin 4√6t < 0.05
solving for t:
τ = t ≈ 0.4045
Explanation:
Given parameters:
Jermaine runs exactly 2 laps around a 400m track
Start time = 3:02:00PM
End time = 3:04:45PM
Unknown:
Distance traveled = ?
Speed = ?
Displacement = ?
Velocity = ?
Solution:
To solve this problem, we need to find the distance and time first;
Distance = 2 x 400 = 800m
Time taken = 3:04:45PM - 3:02:00PM = 165s
Speed = = = 4.85m/s
The velocity of the body is 0m/s and so is the displacement.
This is because the starting and finishing position of the Jermaine is the same.