Answer:
274.08 g of CO2
Explanation:
please see paper for work!
Answer:
Final number of moles = 0.675 mol
Mass = 2.7 g
Explanation:
Given data:
Initial volume of gas = 2.00 L
Final volume of gas = 2.70 L
Initial number of moles = 0.500 mol
Final number of moles = ?
Solution:
Formula:
V₁/n₁ = V₂/n₂
V₁ = Initial volume
n₁ = Initial number of moles
V₂ = Final volume of gas
n₂ = Final number of moles
Now we will put the values in formula.
2.00 L /0.500 mol = 2.70 L / n₂
n₂ = 2.70 L× 0.500 mol /2.00 L
n₂ = 1.35 L.mol / 2.00 L
n₂ = 0.675 mol
B)
Grams of helium added = ?
Solution:
Mass = number of moles × molar mass
Mass = 0.675 mol× 4 g/mol
Mass = 2.7 g
The answer is A but i'm not sure .
Answer:
7/16
Explanation:
The general formula for the combustion of alkanes is;
CnH2n+2 + 3n+1/2 O2 -------> nCO2 + (n+1)H2O
So, we have;
CnHn + nO2 ------> 7CO2 + 8H2O
So there are 7 carbon atoms and 16 hydrogen atoms in heptane according to the law of conservation of mass.
Therefore, heptane is; C7H16
The ratio of carbon to hydrogen is now; 7/16
Co is the symbol for element cobalt. Atomic number of Co is 27.
1st shell has s orbital and can hold up to 2 electrons.
2nd shell has s and p orbital and can hold upto 8 electrons
3rd shell has s, p and d orbital and can hold upto 18 electrons
In Co electronic configuration upto p orbital in 3rd energy shell is
1s² 2s² 2p⁶ 3s² 3p⁶
After 3p orbital, electrons start filling in the s orbital in 4th energy shell as 4s orbital has lower energy than 3d therefore it fills 4s before 3d, after it fills 2 electrons in 4s, remaining electrons fill 3d orbital
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷
in the 3d subshell there are 7 electrons