Since
potassium and phosphate is what we are to find for and they are both found in
the potassium phosphate solution, therefore we solve for this one first on the
basis of the phosphate.
The formula
for finding the volume given the concentration and number of moles is:
Volume =
number of moles / concentration in Molarity
Volume
potassium phosphate required = 30 mmol phosphate / (3 mmol / mL)
<u>Volume
potassium phosphate required = 10 mL</u>
This would
also contain potassium in amounts of:
Amount of
potassium in potassium phosphate = 10 mL (4.4 meg / mL)
Amount of
potassium in potassium phosphate = 44 meg
Therefore
the potassium chloride required is:
Volume of
potassium chloride = (80 meg – 44 meg) / (2 meg / mL)
<span><u>Volume of
potassium chloride = 72 mL</u></span>
Answer:
ΔG° = 1747.523
Explanation:
The parameters mentioned are;
Gibbs Free energy ΔG°
Equilibrium constant Kc
Temperature T = 37 + 273 = 310 (upon conversion to kelvin temperature)
The formular relating all three parameters is given as;
ΔG° = -RTlnKc
Where; R = rate constant = 8.314 J⋅K−1⋅mol−1
Upon solving;
ΔG° = - 8.314 * 310 * ln(1.97)
ΔG° = 1747.523
D i took the test Enjoy :))))
