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MrRa [10]
3 years ago
14

How can you make clay float in water?​

Chemistry
1 answer:
erastovalidia [21]3 years ago
7 0
To make clay float in water you have to shape it into something wide enough and roughly bowl-shaped so that it can displace enough water to compensate for its mass, just like a real boat.
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plz help me asap (plz don't give me helpless answer plz and ty) and also ill give brainist to the person that work hard
Vesna [10]
Question? I don’t see anything
8 0
2 years ago
How do elements heavier than iron form?
Vilka [71]

Answer:

<h2><u>neutron capture </u></h2>

<u></u>

Explanation:

<em>Hope this helps :)  </em>

<em>Pls make brainliest :3  </em>

<em>And have an amazing day <3</em>

4 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
4 years ago
Choose all the answers that apply.
iVinArrow [24]

Answer:it all above

Explanation:

it all above because all the answer are truth so it all above

8 0
3 years ago
Read 2 more answers
A sample of H2 gas (2.0 L) at 3.5 atm was combined with 1.5 L of N2 gas at 2.6 atm pressure at a constant temperature of 25 °C i
Tamiku [17]
For this system, we use Dalton's law of partial pressures where the total pressure of a gas mixture is said to be equal to the sum of the partial pressures of the gases. The partial pressure of each gas would be calculated by the product of the mole fraction and the original pressure of the gas. We do as follows:

Total pressure = x1P1 + x2P2
Total pressure = (2.0 / 7.0 )(3.5) + (1.5/7.0)(2.6)
Total pressure = 1.56 atm
4 0
4 years ago
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