Answer: 0.025 moles of nitrogen gas are there in the sample.
Explanation:
According to ideal gas equation:
P = pressure of gas = 1.03 atm
V = Volume of gas = 568 ml = 0.568 L (1L=1000ml)
n = number of moles = ?
R = gas constant =
T =temperature =
0.025 moles of nitrogen gas are there in the sample.
Answer:
thats all help me too:)...............
Answer:
569K
Explanation:
Q = 3.5kJ = 3500J
mass = 28.2g
∅1 = 20°C = 20 + 273 = 293K
∅2 = x
c = 0.449
Q = mc∆∅
3500 = 28.2×0.449×∆∅
3500 = 12.6618×∆∅
∆∅ = 3500/12.6618
∆∅ = 276.4220
∅2 - ∅1 = 276.4220
∅2 = 276.4220 + ∅1
∅2 = 276.4220 + 293
∅2 = 569.4220K
∅2 = 569K
Answer:
a) 26.98
b) 3
c) 3* 1.01 = 3.03
d) 3 *16 = 48
e) 26.98 + 3.03 + 48 = 78.01
f) 6.023 * 10²³
The options are labelled as:
1 2
3 4
5 6
7 8
Protons: 1, 5, 7
Neutrons: 2, 8
Electron: 3, 4, 6
