The solubility constant of MnS is 2.3 ×10−13 at 25°C. What is the concentration of sulfide
1 answer:
[A] + [B] ⇌ [C] + [D]
MnS ⇌ Mg + S
Ksp = [C][D]
Ksp = (Mn)(S)
2.3*10^-13 = (x)(x)
2.3*10^-13 = x^2
x = 4.8*10^-7
Concentration of sulfide is x.
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Answer: The pH of a 4.4 M solution of boric acid is 4.3
Explanation:
at t=0 cM 0 0
at eqm 
So dissociation constant will be:
Give c= 4.4 M and 
= ?
Putting in the values we get:
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
![[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D4.4%5Ctimes%200.000011%3D4.8%5Ctimes%2010%5E%7B-5%7DM)
Also ![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![pH=-log[4.8\times 10^{-5}]=4.3](https://tex.z-dn.net/?f=pH%3D-log%5B4.8%5Ctimes%2010%5E%7B-5%7D%5D%3D4.3)
Thus pH of a 4.4 M 
solution is 4.3
I need to find the x pls help and show work 73838
Answer:
cl2 - 1 bond
HCl.- 1 bond
N2 - 3 bond
o2 - 2 bond
- Cl requires one electron to complete it's octave so it share it's one electron with other chlorine and make a single covalent bond
- H has one electron and Cl requires one so both form one single bond
- N requires 3 electrons so it form 3 bonds with other N
- oxygen requires 2 electrons so it forms 2 bond with other oxygen
