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Goryan [66]
3 years ago
12

The gas tank of a car is filled with a nozzle that discharges gasoline at a constant flow rate. Based on unit considerations of

quantities, choose the correct relation for the filling time in terms of the volume V of the tank (in L) and the discharge rate
Physics
1 answer:
mojhsa [17]3 years ago
4 0

Answer:

V=\dfrac{dV}{dt}.t

Explanation:

Given that nozzle discharge at constant flow rate.

Volume of tank is V

Lets  constant flow rate =Q

We know that

Q=\dfrac{dV}{dt}\ L^3/s

To find the time t,at a volume V

V = Q .t

V=\dfrac{dV}{dt}.t

Where t is the filling time of volume .

dV/dt is the volume floe rate .

Q is the discharge.

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Answer:

<span>C) Both have rocky composition 

Explanation

Earth has rocks. Many many rocks.

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True or false as heat and pressure decreases one type of metamorphic rock will transform into another type
dezoksy [38]

Answer: True

Explanation:  Metamorphism is the changing of rocks by heat and pressure. During this process, rocks change either physically and/or chemically. They change so much that they become an entirely new rock. Figure 4.22: The platy layers in this large outcrop of metamorphic rock show the effects of pressure on rocks during metamorphism.

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3 years ago
Rearrange the kinetic energy equation so that velocity is the subject
mars1129 [50]

Answer: V = sqrt(2K.E/M)

Explanation:

K.E = 1 /2MV^2

MV^2 = 2 K.E

V^2 = 2K.E /M

V = sqrt(2K.E/M)

6 0
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Storms are caused by. I WILL MARK BRAINLIEST
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8 0
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A heat engine is operating on a Carnot cycle and has a thermal efficiency of 47 percent. The waste heat from this engine is reje
Fantom [35]

Answer:

Explanation:

Given that,

Efficiency of Carnot engine is 47%

η =47%=0.47

The wasted heat is at temp 60°F

TL=60°F

Rate of heat wasted is 800Btu/min

Therefore, rate of heat loss QL is

QL' = 800×60 =48000

The power output is determined from rate of heat obtained from the source and rate of wasted heat.

Therefore,

W' = QH' - QL'

Note QH' = QL' / (1-η)

W' = QL' / (1-η) - QL'

W'=QL' η / (1-η)

W'= 48000×0.47/(1-0.47)

W'=42566.0377 BTU

1 btu per hour (btu/h) = 0.00039 horsepower (hp)

Then, 42566.0377×0.00039

W'=16.6hp

Which is approximately 17hp

b. Temperature at source

Using ratio of wanted heat to temp

Then,

TH / TL = QH' / QL'

TH = TL ( QH' / QL')

Since, QH' = QL' / (1-η)

Then, TH= TL( QL' /QL' (1-η))

TH=TL/(1-η)

TL=60°F, let convert to rankine

°R=°F+459.67

TL=60+459.67

TL=519.67R

TH=519.67/(1-0.47)

TH=980.51R

Which is approximately 1000R

6 0
3 years ago
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