
Initial velocity of a car is 36 km/h . Find the distance after min, if it goes with acceleration 2 m/s².

Initial velocity, u = 36 km/h

Time, t = 1min
Acceleration, a = 2m/s²
Apply 2nd equation of motion

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Answer:
The stronger person holds it closer to them.
Explanation:
if the stronger person were to hold the ladder closer to them, they would be holding more of the weight thus making the weaker person have less weight. this is because of the center of gravity being closer to the stronger person.
Answer:
T₂ = 111.57 °C
Explanation:
Given that
Initial pressure P₁ = 9.8 atm
T₁ = 32°C = 273 + 32 =305 K
The final pressure P₂ = 11.2 atm
Lets take the final temperature = T₂
We know that ,the ideal gas equation
If the volume of the gas is constant ,then we can say that


Now by putting the values in the above equation ,we get


T₂ = 384.57 - 273 °C
T₂ = 111.57 °C