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Butoxors [25]
3 years ago
15

What is the approximate mass of 25 cm3 of silver, in the density is 10.05g cm3?

Chemistry
1 answer:
Rudik [331]3 years ago
8 0
4 3 4 111.6 3 r = 111.6 cm3<span> = (3.1416)r3 r= 3 = 2.987 cm V= 3 3 4(3.1416) 3A ... with it absent. </span>density<span> =</span>mass<span> 28.4 g rock = = 2.76 g/mL = 2.76 g/</span>cm3<span> volume 44.1 ... can be found using dimensional analysis. ethanol </span>mass<span> = </span>25<span> L gasohol 1000 mL ..... 100.00 g solution = 9.95 103 g solution 1 kg sucrose </span>10.05 g<span>sucrose 53.</span>
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3 years ago
Read 2 more answers
solution of 0.160 MNaOH is used to titrate 21.0 mL of a solution of H2SO4:H2SO4(aq)+2NaOH(aq)→2H2O(l)+Na2SO4(aq)If 38.8 mL of th
stealth61 [152]

Answer:

0.0432 M H2SO4

Explanation:

First, we want to find the moles of MNaOH used. We know that Molarity x Liters = moles. 0.160M x 0.0210L = 0.00336 moles MNaOH

to find the moles of H2SO4, we can use a mol ratio.

0.00336mol MNaOH x (1Mol H2SO4 /2mol MNaOH)

= 0. 00168 mol H2SO4

I found the mol ratio by looking at the coefficients in front of the molecules I knew(MNaOH) and the molecule I needed to find(H2SO4)

then, to find Molarity, we do mol/Liters

0.00168 mol/ 0.0388L =. 0.0432 M H2SO4

You can convert mL to L by dividing by 1000

the significant figures of this problem is 3, so my final answer will also have 3 sig figs.

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