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1 year ago

The carbon atoms in graphite and the carbon atoms in diamond have different

Chemistry

1 answer:

kicyunya [14]1 year ago

7 0

Answer:

<u>structural arrangements</u>

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<h2>properties of daimond: </h2><h3>appearance: transparent</h3><h3>hardness: very hard</h3><h3>thermal conductivity :very poor</h3><h3>electric conductivity: poor</h3><h3>density:</h3>

$3510 {kgm}^{3}$

<h3>uses: jewellery and drilling</h3>

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<h2>properties of graphite:</h2>

<h3>appearance: black shiny</h3><h3>hardness: soft ,slippery to touch</h3><h3>thermal conductivity : moderate</h3><h3>electric conductivity: good</h3><h3>density:</h3>

$2250 {kgm}^{3}$

<h3>uses:dry cell, electric arc, pencil lead, lubricant</h3>

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<h2>How Diamond and Graphite are chemically identical?</h2>

On heating diamond or graphite in the air, they burn completely to form carbon dioxide.
- Equal quantities of diamond and graphite when burned, produce exactly the same amount of carbon dioxide.

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<h2>Why the physical properties of diamond and graphite are so different?</h2>

Due to the difference in the arrangement of carbon atoms in diamond and graphite

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<h2><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>

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Answer:

e. 22s

Explanation:

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The integrated rate law for second order reactions is given as;

1 / [A] = (1 / [A]o) + kt

Making k subject of interest, we have;

kt = (1 / [A] ) - (1 / [A]o )

k = (1 / [A] ) - (1 / [A]o ) / t

k = [(1/ 15) - (1 / 100) ] / 720

k = (0.0667 - 0.01 ) / 720

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k = 7.875e^-5

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Final concentration = 85 (Since the reaction would be 15% complete)

The integrated rate law for second order reactions is given as;

1 / [A] = (1 / [A]o) + kt

Making t subject of interest, we have;

kt = (1 / [A] ) - (1 / [A]o )

t = (1 / [A] ) - (1 / [A]o ) / k

t = [(1 / 85 ) - (1 / 100) ] / 7.875e^-5

t = (0.0117 - 0.01 ) / 7.875e^-5

t = 0.001765 / 7.875e^-5

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4. Solve the following heat flow problem, being sure to show all your work (you may either type your

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Answer:

0.70 J/g.°C

Explanation:

Step 1: Given data

Mass of graphite (m): 402 g

Heat absorbed (Q): 1136 J

Initial temperature: 26°C

Final temperature: 30 °C

Specific heat of graphite (c): ?

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