Answer:
the Answer is B because that what I know
Answer:
8.77 kilo Joules will be the total amount of heat required for both the heating and the vaporizing.
Explanation:
Moles of ethanol of ethanol = 0.200 mol
Heat required to heat 0.200 moles of ethanol = Q = 1.05 kJ
Enthalpy of vaporization of ethanol =
Heat required to vaporize 0.200 moles of ethanol = Q'
Total heat required to fore heating and the vaporizing :
= Q + Q' = 1.05 kJ + 7.72 kJ = 8.77 kJ
8.77 kilo Joules will be the total amount of heat required for both the heating and the vaporizing.
Explanati la materia el convino
es carbón ya irogno
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The units of light energy emitted by blackbody radiation is originally called as quanta. Black body radiation is a type of radiation within a boy in thermodynamic equilibrium. This is a theoretical body. In 1900, Planck proposed that light and other electromagnetic waves were emitted in discrete packets of energy which were called "quanta". This was the original unit used.