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Sauron [17]
3 years ago
14

I need help with B and C

Chemistry
1 answer:
lakkis [162]3 years ago
8 0
B) Mg is the alkaline earth metal w/12 protons so following the periodic table to the halogen in the same period is

Cl: Chlorine

C) The Neutral noble has w/ 18 electrons is argon so the metal in the same row is

Na: Sodium
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What element has an electron<br> configuration of 2-8-8-1:
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Ойлголоо, уучлаарай Ойлголоо, уучлаарай /; coo
4 0
2 years ago
A certain ore is 37.3% nickel by mass how many kilograms of this ore would you need to dig up to have 10.0g of nickel
jeka57 [31]
If the grade of the ore is 37.3% nickel, then the unknown quantity to get 10 grams of nickel is 0.373 x = 10 grams or x = 10/0.373=26.8 grams or 0.0268 kg needed to dig up to recover the 10 grams of nickel. At this grade of ore, 1 kilogram would yield 373 grams of nickel. 
7 0
3 years ago
Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi
bija089 [108]

<u>Answer:</u> The value of K_c for the net reaction is \frac{K_b}{K_w}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b

<u>Equation 2:</u>  H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}

The net equation follows:

B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=K_1\times K_2

We are given:  

K_1=K_b

K_2=\frac{1}{K_w}

Putting values in above equation, we get:

K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}

Hence, the value of K_c for the net reaction is \frac{K_b}{K_w}

7 0
3 years ago
What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy
daser333 [38]
Moles   =  n  = 3.91 mol

                  Pressure  =  P  =  5.35 atm

                  Temperature  =  T  =  323 K

                  Volume  =  V  =  ?

Formula used: Ideal Gas Equation is used,

                                        P V  = n R  T
Solving for V,
                                           V  =  n R T / P
Putting Values,
                           V  =  (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm

                         V  =  19.36 L

5 0
3 years ago
Calculate the quantity of energy required to change 8.22 mol of liquid water to steam at 100oc. the molar heat of vaporization o
Ainat [17]
Since  the water  is  at  100 degrees  then   it take  40.6 kj/mol   to  change 1  mole of  water at 100 degrees into  steam at  100  degrees
  the  moles  of water  8.22mol
since  one  mole  take 40.6kj/mol   8.22mol  will  be  =
8.22mol  x  40.6 kj/mol =333.732  kj
 
4 0
3 years ago
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