Gold is a mixture Becasue it contains more than one element
Answer;
D, Xe (g)
Solution and explanation;
If 2g has a volume of 340ml.
Density is 1000/340*2 = 5.88g/litre.
-This rules out the two solids, choices 2) &3)
If 1 litre has mass 5.88g,
then 22.4 liters (volume at STP) has mass 5.88*22.4 = 131.8g/mol
molar mass Br2 = 80*2 = 160g/mol NO
molar mass Xe = 131.3g/mol = YES.
Answer is Xe
Answer: b. False
K+ ions move faster than the Na+ ions through the neuron membranes.
The concentration of Sodium ions outside the cell is very high. The concentration of Potassium ions inside the cells is very high. Leakage channels thus allow sodium ions to move inside the cells and pumps out the Potassium from the cells.
The grams of the sugar in 125 g of the drink is calculated as below
%M/m) = mass of the solute (sugar)/ mass of the solvent(drink) x100
let the mass of the solute(sugar) be represented by y
convert % into fraction by dividing by 100 = 10.5/100
10.5/100 = y/125
by cross multiplication
100y =1312.5
divide both side by 100
y=13.125 grams
When solid carbon reacts with oxygen gas to produce carbon dioxide gas. the deltaH (enthalpy change ) value is negative .DeltaH would be on the product side of the equation.
<h3>What is enthalpy change? </h3>
In a thermodynamic system, energy is measured by enthalpy. Enthalpy is a measure of a system's overall heat content and is equal to the system's internal energy plus the sum of its volume and pressure.
Knowing whether q is endothermic or exothermic allows one to characterise the relationship between q and H. An endothermic reaction is one that absorbs heat and demonstrates that heat from the environment is used in the reaction, hence q>0 (positive). For the aforementioned equation, under constant pressure and temperature, if q is positive, then H will also be positive. In a similar manner, heat is transferred to the environment when it is released during an exothermic reaction. Thus, q=0 (negative). Therefore, if q is negative, H will also be negative.
Learn more about enthalpy change here :
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