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Brums [2.3K]
3 years ago
7

Which is the best example of increasing entropy?

Physics
2 answers:
andreev551 [17]3 years ago
3 0

Answer:A campfire

Explanation:

nekit [7.7K]3 years ago
3 0

Answer:

Transferring heat to a body.

Step by step answer:

Entropy refers to the degree of disorder of a system. This increases when we move from a state of greater order to one of a greater degree of disorder.

By heating a body, this causes the energy of the body to increase. This means that the speed of the molecules that compose it increases and makes them collide more frequently between them, creating an increase in the degree of disorder that exists.

A clear example of heat transfer is when a body changes its state and moves from an orderly state to one of greater disorder.

 For example:

  • Moving from a solid state to a liquid state:

Melt an ice cube

  • Move from liquid to gaseous:

Heat water until it starts to boil and turns into steam

You do not necessarily have to change the state to increase the entropy.

For example when heating water without boiling.

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When a switch is closed to complete a DC series RL circuit which has a large time constant, Group of answer choices the electric
puteri [66]

Answer:

The electric and magnetic fields gradually increase.

Explanation:

Time constant in RL circuits, denoted by τ, is equal to the value of L / R which is the value of the inductor over the resistor. It is used to calculate the point when the current will reach the maximum value in the steady state of the circuit. Because of this behavior of the circuit, the magnetic field and the electric field gradually increase to their maximum values.

I hope this answer helps.

3 0
4 years ago
Runner x starts 50 feet in front of runner z and moves with a velocity of 8.0 m/s. At what speed would runner z have to run to c
Mariulka [41]

Answer:

15.625

Explanation:

8 0
3 years ago
What are the potential obstacles preventing you from completing your exercises as scheduled? How can you overcome those obstacle
shusha [124]

Answer:

Sleep, behavior patterns, mental state, and job

Explanation:

3 0
3 years ago
A rectangular key was used in a pulley connected to a line shaft with a power of 7.46 kW at a speed of 1200 rpm. If the shearing
Damm [24]

Given:

Shaft Power, P = 7.46 kW = 7460 W

Speed, N = 1200 rpm

Shearing stress of shaft, \tau _{shaft} = 30 MPa

Shearing stress of key, \tau _{key} = 240 MPa

width of key, w = \frac{d}{4}

d is shaft diameter

Solution:

Torque, T = \frac{P}{\omega }

where,

\omega = \frac{2\pi  N}{60}

T = \frac{7460}{\frac{2\pi  (1200 )}{60}} = 59.365 N-m

Now,

\tau _{shaft} = \tau _{max} = \frac{2T}{\pi (\frac{d}{2})^{3}}

30\times 10^{6} = \frac{2\times 59.365}{\pi (\frac{d}{2})^{3}}

d = 0.0216 m

Now,

w =  \frac{d}{4} =  \frac{0.02116}{4} = 5.4 mm

Now, for shear stress in key

\tau _{key} = \frac{F}{wl}

we know that

T = F \times r =  F. \frac{d}{2}

⇒ \tau _{key} = \frac{\frac{T}{\frac{d}{2}}}{wl}

⇒ 240\times 10^{6} = \frac{\frac{59.365}{\frac{0.0216}{2}}}{0.054l}

length of the rectangular key, l = 4.078 mm

7 0
3 years ago
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notsponge [240]

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