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2 years ago

Select all that apply.

Chemistry

2 answers:

Y_Kistochka [10]2 years ago

8 0

No chemical bonding take place.
And the elements or compounds in the mixtures have no definite proportions.

krek1111 [17]2 years ago

4 0

I would go with B. The elements of sugar and water have been known for a long time, so A is irrelevant. Mixtures can contain compounds- most of the time mixtures are composed of compounds mixed together, so C is false as well. Chemical formulas are designed to handle different proportions- that's why they have the numbers before the chemical name, such as 2H2O. B is your best bet for this one, as a mixture is more than one chemical combined but not bonded.

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Here are some data from a similar experiment, to determine the empirical formula of an oxide of tin. Calculate the empirical for

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Answer:

Empirical formula of the Tin oxide sample is SnO₂

Explanation:

Tin reacts with combines with oxygen to form an oxide of tin.

Mass of crucible with cover = 19.66 g

Mass of crucible, cover, and tin sample = 22.29 g

Mass of crucible and cover and sample, after prolonged heating gives constant weight = 21.76 g

Mass of Tin oxide sample = 22.29 - 19.66 = 2.63 g

Mass of ordinary tin, after heating to breakdown the tin and oxygen = 21.76 - 19.66 = 2.1 g

Meaning that, mass of oxygen in the tin oxide sample = 2.63 - 2.1 = 0.53 g

Mass of Tin in the Tin Oxide sample = 2.1 g

Mass of Oxygen in the Tin oxide sample = 0.53 g

Convert these to number of moles

Number of moles of Tin on the Tin oxide sample = 2.1/118.71 = 0.0177

Number of moles of Oxygen in the Tin oxide sample = 0.53/16 = 0.0335

divide the number of moles by the lowest number

0.0177:0.0335

It becomes,

1:2

SnO₂

Hence, the empirical formula for the Tin oxide sample = SnO₂

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valence electron : 5

<h3>Further explanation </h3>

Valence electrons : electrons used in forming bonds (the outer shell)

Core electrons : electrons that belong to atoms except for valence electrons. It is located close to the core and fills the inner shell.

Electron configurations for an element with the atomic number: 15 1s²2s²2p⁶3s²3p³

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