From the stoichiometry of the reaction, we can see that the volume of carbon monoxide reacted is 44.8 L.
<h3>What is stoichiometry?</h3>
Stoichiometry is used to obtain the amount of substance reacted or the amount of product formed.
Number of moles of CO2 in 88g = 88g/4 g/mol = 2 moles
Molar mass of carbon monoxide = 12 + 16 = 28g/mol
We can see that 1 mole of oxygen was used in the reaction hence the mass of oxygen used is 32 g/mol. Given the stoichiometry of the reaction, 28g of carbon monoxide was burned.
If 1 mole of a gas occupies 22.4 L
2 moles of a gas occupies 2 moles * 22.4 L/1 mole
= 44.8 L
Learn more about stoichiometry:brainly.com/question/9743981
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A - its condensation and gas particles have a higher kinetic energy
Answer: secondary structure
Explanation:
From start:
Joule, J, calorie,
Example 1: 120 J / 4.184 = 28.68 cal
Example 2: 1200 cal * 4.184 = 5020.8 J
1) Silicon dioxide formula: SiO2 ....... 2 is a subscript for the O atom
2) From the formula you have 1 molecula of SiO2 contains 1 atom of SiO2
3) Then, 0.100 mol of SiO2 contains 0.1 mol of Si
4) Multiply by Avogadro's number: 0.100mol * 6.022*10^23 atoms/mol= 6.02*10^22 atoms
Answer: 6.02*10^22 atoms
