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3 years ago

A 60 kilogram astronaut weighs 96 newtons on the surface of the moon. calculate the acceleration due to gravity on the moon.

Physics

2 answers:

Charra [1.4K]3 years ago

8 0

Answer:

Acceleration due to gravity on moon, $1.6\ m/s^2$

Explanation:

Mass of the astronaut, m = 60 kg

Weight of astronaut on the surafce of moon, W = 96 N

The weight of astronaut is given by :

W = m g

$g=\dfrac{W}{m}$

$g=\dfrac{96\ N}{60\ kg}$

$g=1.6\ m/s^2$

So, the acceleration due to gravity on the surface of moon is $1.6\ m/s^2$

Also, the acceleration due to gravity on the surface of moon is (1/6)th of the acceleration due to gravity on the surface of earth.

Hence, this is the required solution.

34kurt3 years ago

6 0

Given: Mass m = 60 Kg

Weight W = 96 N

Required: Acceleration due to gravity, g = ?

Formula: W = mg

g = W/g

g = 96 Kg.m/s²/60 Kg (note: this is the derive unit for Newton "N")

g = 1.6 m/s²

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He throws a second ball (B2) upward with the same initial velocity at the instant that the first ball is at the ceiling. c. How

Gwar [14]

Answer:

hello your question has some missing parts

A juggler performs in a room whose ceiling is 3 m above the level of his hands. He throws a ball vertically upward so that it just reaches the ceiling.

answer : c) 0.39 sec

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Explanation:

The initial velocity of the first ball = 7.67 m/sec ( calculated )

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Determine how long after the second ball is thrown do the two balls pass each other

Distance travelled by first ball downwards when it meets second ball can be expressed as : d = 1/2 gt^2 = 9.8t^2 / 2

hence d = 4.9t^2 ----- ( 1 )

Initial speed of second ball = first ball initial speed = 7.67 m/sec

3 - d = 7.67t - 4.9t ---- ( 2 )

equating equation 1 and 2

3 = 7.67t therefore t = 0.39 sec

Determine how far the balls are above the Juggler's hands ( when the balls pass each other )

form equation 1 ;

d = 4.9 t^2 = 4.9 *(0.39)^2 = 0.75 m

therefore the height the balls are above the Juggler's hands is

3 - d = 3 - 0.75 = 2.25 m

determine their velocities when the pass each other

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Answer:

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Answer:

the Answer Would be D

Explanation:

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A 5.00 gram bullet moving at 600 m/s penetrates a tree trunk to a depth of 4.00 cm.

Crazy boy [7]

A) Work energy relation;
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F = Ma
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= 4,500,000 m/s²
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4 years ago

A metal rod of length (L) moves with velocity (v), perpendicular to its length, in a magnetic field B, which is perpendicular to

Alborosie

Explanation:

If a metal rod of length L moves with velocity v is moving perpendicular to its length, in a magnetic field B, the induced emf is given by :

$\epsilon=Blv$

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3 years ago