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2 years ago

A 60 kilogram astronaut weighs 96 newtons on the surface of the moon. calculate the acceleration due to gravity on the moon.

Physics

2 answers:

Charra [1.4K]2 years ago

8 0

Answer:

Acceleration due to gravity on moon, $1.6\ m/s^2$

Explanation:

Mass of the astronaut, m = 60 kg

Weight of astronaut on the surafce of moon, W = 96 N

The weight of astronaut is given by :

W = m g

$g=\dfrac{W}{m}$

$g=\dfrac{96\ N}{60\ kg}$

$g=1.6\ m/s^2$

So, the acceleration due to gravity on the surface of moon is $1.6\ m/s^2$

Also, the acceleration due to gravity on the surface of moon is (1/6)th of the acceleration due to gravity on the surface of earth.

Hence, this is the required solution.

34kurt2 years ago

6 0

Given: Mass m = 60 Kg

Weight W = 96 N

Required: Acceleration due to gravity, g = ?

Formula: W = mg

g = W/g

g = 96 Kg.m/s²/60 Kg (note: this is the derive unit for Newton "N")

g = 1.6 m/s²

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Gennadij [26K]

Answer:

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The rotational speed needed is :

$9.8 \frac{m}{s^2} = \omega ^2 * 110 \ m$

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$\omega = \sqrt{ 0.08909 \frac{rad^2}{s^2} }$

$\omega = 0.2985 \frac{rad}{s}$

Knowing that there are $2\pi \ rad$ in a revolution and 60 seconds in a minute.

$\omega = 0.2985 \frac{rev}{min} \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}$

$\omega = 2.8502 \frac{rev}{min}$

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