"Given a nodal delay of 84.1ms when there is no traffic on the network (i.e. usage = 0%), what is the effective delay when netwo
1 answer:
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Answer:
i) 25.04 W/m^2 .k
ii) 23.82 minutes = 1429.2 secs
Explanation:
Given data:
Diameter of steel ball = 15 cm
uniform temperature = 350°C
p = 8055 kg/m^3
Cp = 480 J/kg.k
surface temp of ball drops to 250°C
average surface temperature = ( 350 + 250 ) / 2 = 300°C
<u>i) Determine the average convection heat transfer coefficient during the cooling process</u>
<em>Note : Obtain the properties of air at 1 atm at average film temp of 30°C from the table " properties of air " contained in your textbook</em>
average convection heat transfer coefficient = 25.04 W/m^2 .k
<u>ii) Determine how long this process has taken </u>
Time taken by the process = 23.82 minutes = 1429.2 seconds
Δt = Qtotal / Qavg = 683232 / 477.92 = 1429.59 secs
attached below is the detailed solution of the given question
Answer:
Matlab code with step by step explanation and output results are given below
Explanation:
We have to construct a Matlab function that creates a row vector "countValues" with elements 1 to endValue. That means it starts from 1 and ends at the value provided by the user (endValue).
function countValues = CreateArray(endValue)
% Here we construct a row vector countValues from 1:endValue
countValues = 1:endValue;
% then we transpose this row vector into column vector
countValues = countValues';
end
Output:
Calling this function with the endValue=11 returns following output
CreateArray(11)
ans =
1
2
3
4
5
6
7
8
9
10
11
Hence the function works correctly. It creates a row vector then transposes it and makes it a column vector.
