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SCORPION-xisa [38]
3 years ago
13

A stainless steel ball (=8055 kg/m3, Cp= 480 J/kgK) of diameter D =15 cm is removed from theoven at a uniform temperature of 3

50oC. The ball is then subjectedto the flow of air at 1 atm pressure and 30oC with a velocityof 6 m/s. The surface temperature of the ball eventuallydrops to 250oC. Determine the average convection heat transfercoefficient during this cooling process and estimate howlong this process has taken.
Engineering
1 answer:
aleksandrvk [35]3 years ago
3 0

Answer:

i) 25.04 W/m^2 .k

ii) 23.82 minutes = 1429.2 secs

Explanation:

Given data:

Diameter of steel ball = 15 cm

uniform temperature = 350°C

p = 8055 kg/m^3

Cp = 480 J/kg.k

surface temp of ball drops to  250°C

average surface temperature = ( 350 + 250 ) / 2 = 300°C

<u>i) Determine the average convection heat transfer coefficient during the cooling process</u>

<em>Note : Obtain the properties of air at 1 atm at average film temp of 30°C from the table  " properties of air "  contained in your textbook</em>

average convection heat transfer coefficient = 25.04 W/m^2 .k

<u>ii) Determine how long this process has taken </u>

Time taken by the process = 23.82 minutes = 1429.2 seconds

Δt = Qtotal / Qavg = 683232 / 477.92 = 1429.59 secs

attached below is the detailed solution of the given question

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Answer:

The following program written in c++:

#include <iostream>

using namespace std;

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{

private :      //access modifier

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public :

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{

pi = 3.1415;

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}

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{

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private:       //access modifier

double length ,breadth ,area; // set double type private data types

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Rectangle (double length = 0.0, double breadth = 0.0) // define constructor

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{

int choice;      //integer type variable

double radius, length, breadth;

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cin >> choice;

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cin >> length >> breadth;

r.setDimension(length,breadth);

cout << "Area of rectangle is : " << r.getArea();

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}

return 0;

}

Explanation:

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