Responder:
A) ω = 565.56 rad / seg
B) f = 90Hz
C) 0.011111s
Explicación:
Dado que:
Velocidad = 5400 rpm (revolución por minuto)
La velocidad angular (ω) = 2πf
Donde f = frecuencia
ω = 5400 rev / minuto
1 minuto = 60 segundos
2πrad = I revolución
Por lo tanto,
ω = 5400 * (rev / min) * (1 min / 60s) * (2πrad / 1 rev)
ω = (5400 * 2πrad) / 60 s
ω = 10800πrad / 60 s
ω = 180πrad / seg
ω = 565.56 rad / seg
SI)
Dado que :
ω = 2πf
donde f = frecuencia, ω = velocidad angular en rad / s
f = ω / 2π
f = 565.56 / 2π
f = 90.011669
f = 90 Hz
C) Periodo (T)
Recordar T = 1 / f
Por lo tanto,
T = 1/90
T = 0.0111111s
Answer:
The horizontal distance is 0.64 m.
Explanation:
Initial velocity, u =2.5m/s
The maximum horizontal distance is
The answer is Rh = 135 cm^3 and B = 0.05185 wh/m^2
Explanation:
Resitivity of silicon = 0.1
thickness = 100um
so, I = ma
Required to find out concentration of electron , we know that
Rh = up
By putting in the values,
Rh = 1350 x 0.1
Rh = 135 cm^3
Now consider,
Rh = 1 / Rh.q
= 1 / Rh . q
= 1 / 135 x1.609 x10^-19
= 4.6037 x 10^16 / cm^3
Vh = BIRh / w
B = Vh w/ IRh
B = -70 x10^-6 x 100 x10^-6 / 1x 10^-3 x 135 x 10^-6
B = 0.05185 wh / m^2
Answer:
ill get back to this question once i get the answer
