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2 years ago

Please look at the picture and answer the questions

Physics

1 answer:

Alborosie2 years ago

6 0

Answer:

Which sentence from the passage shows that the function of the river depicted here has carried through to modern times?

Explanation:

Which sentence from the passage shows that the function of the river depicted here has carried through to modern times?

You might be interested in

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics

olga nikolaevna [1]

Answer:112.82 m/s

Explanation:

Given

range of arrow=68 m

$Angle=3^{\circ}$

as the arrow travels it acquire a vertical velocity $v_y$

$v_y=u+at$

$v_y=0+9.81\times t$ -------1

Range is given by

R=ut

where u=initial velocity

$68=u\times t$

$t=\frac{68}{u}$

substitute the value of t in eqn 1

$v_y=9.81\times \frac{68}{u}$

$v_y\times u=9.81\times 68=667.08$ --------2

and $tan(3)=\frac{v_y}{u}$

$v_y=utan(3)=0.0524u$

substitute it in 2

$0.0524 u^2=667.08$

$u^2=12,728.644$

u=112.82 m/s

6 0

3 years ago

Why can't 41 be represented in a binary table?

Airida [17]

Answer:

I think it is but I don't know for sure

Explanation:

41 101001

41 is 101001 on the binary table i think

8 0

2 years ago

What is the magnitude of the resultant of a 7.0-N force acting vertically upward and a 5.0-N force acting horizontally.

irakobra [83]

Answer:

Resultant force = 8.6N

Explanation:

Using Pythogorus' theorem

${a}^{2} + {b}^{2} = {c }^{2} \\ {7}^{2} + {5}^{2} = {r}^{2} \\ 49 + 25 = {r}^{2} \\ 74 = {r}^{2} \\ \sqrt{74} = \sqrt{ {r }^{2} } \\ 8.6 = r \\$

Resultant force = 8.6N

6 0

2 years ago

Studen

Vesna [10]

Complete Question

A football coach walks 18 meters westward, then 12 meters eastward, then 28 meters westward, and finally 14 meters eastward.

From this motion what is the distance covered

What is the magnitude and direction of the displacement

Answer:

$D = 72 \ m$

Magnitude

$d = - 20 \ m$

Direction

West

Explanation:

From the question we are told that

The first distance covered westward is $d_w_1 = 18 \ m /tex] The first distance covered eastward is [tex]d_e1 = 12 \ m /tex] The second distance covered westward is [tex]d_w_2 = 28 \ m /tex] The second distance covered eastward is [tex]d_e2 = 14 \ m /tex] Generally the distance covered is mathematically represented as [tex]D = d_w1 + d_w2 + d_e1 + d_e2$

=> $D = 18 + 28 + 12 + 14$

=> $D = 72 \ m$

For the second question eastward is in the direction of the positive x-axis so it would be positive and westward is in the direction of the negative x-axis so it would be negative

The magnitude of the displacement is

$d = -d_w1 -d_w2 + d_e1 + d_e2$