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nika2105 [10]
3 years ago
4

When a chemist collects hydrogen gas over water, she ends up with a mixture of hydrogen and water vapor in her collecting bottle

. If the pressure in the collecting bottle is 97.1 kilopascals and the vapor pressure of the water is 3.2 kilopascals, what is the partial pressure of the hydrogen?
A.
93.9 kPa
B.
98.1 kPa
C.
100.3 kPa
D.
104.5 kPa
Chemistry
2 answers:
PSYCHO15rus [73]3 years ago
7 0

Answer:

a

Explanation:

rjkz [21]3 years ago
5 0
The total pressure inside the bottle is due to water vapors and hydrogen both.

The total pressure is 97.1 kilopascals (kPa). The partial pressure is the contribution of any gas or vapor to the total pressure.

Water vapors has a vapor pressure of 3.2 kPa. That is the contribution coming from water vapors. The total pressure minus the water vapor pressure would give us the partial pressure of hydrogen.

The answer would be (97.1 kPa - 3.2 kPa) = 93.9 kPa.
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Answer:

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Explanation:

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Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of nitrogen gas = 79mL/s

R_2 = rate of effusion of sulfur dioxide gas = ?

M_1 = molar mass of nitrogen gas  = 28 g/mole

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Now put all the given values in the above formula 1, we get:

(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}

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