Explanation :
As we know that the Gibbs free energy is not only function of temperature and pressure but also amount of each substance in the system.
where,
is the amount of component 1 and 2 in the system.
Partial molar Gibbs free energy : The partial derivative of Gibbs free energy with respect to amount of component (i) of a mixture when other variable 
are kept constant are known as partial molar Gibbs free energy of 
component.
For a substance in a mixture, the chemical potential 
is defined as the partial molar Gibbs free energy.
The expression will be:
where,
T = temperature
P = pressure
is the amount of component 'i' and 'j' in the system.
Lustrous (shiny)
Good conductors of heat and electricity.
High melting point.
High density (heavy for their size)
Malleable (can be hammered)
Ductile (can be drawn into wires)
Usually solid at room temperature (an exception is mercury)
Opaque as a thin sheet (can't see through metals)
they are outside the body, because they need to be cooler than the temperature inside the body so sperm can be made. hope this helped you <3
<u>Residual soil and transported soil differ by as follows:</u>
Residual soil stays over its parent rock and transported soil forms from particles from another place.
<u>Explanation:</u>
Soil forms from weathering of rock. When a rocks get weathered it creates small paiticles. That forms different kind of soil. Soil varies in texture, structure, colour, composition and in pH level. Each and every soil type produced from parent rock. Depending upon the character of parent rock soil type is determined like basalt the igneous rock forms black soil.
Residual soil stays over parent rock it does not get off by the activities of natural agents like air, water, wind and glacier. Transported soil comes from hilly area to flat topped ground by transportation through some transporting agents of nature. It is immature soil.
Answer:
0.66g/mL
Explanation:
La densidad es una propiedad de la materia definida como la masa de una sustancia en un determinado volumen.
En este problema, podemos hallar la densidad sabiendo que la diferencia de masas del pic vacío y el pic lleno es la masa de la solución y que el volumen que ocupa es de 25mL:
<em>Masa solución:</em>
25g - 8.5g = 16.5g
Así, la densidad será:
16.5g / 25mL =
<h3>0.66g/mL</h3>
