Answer:
Frictional force, F = 45.9 N
Explanation:
It is given that,
Weight of the box, W = 150 N
Acceleration,
The coefficient of static friction between the box and the wagon's surface is 0.6 and the coefficient of kinetic friction is 0.4.
It is mentioned that the box does not move relative to the wagon. The force of friction is equal to the applied force. Let a is the acceleration. So,
Frictional force is given by :
F = 45.9 N
So, the friction force on this box is closest to 45.9 N. Hence, this is the required solution.
Answer:
Explanation:
Q1 = 35 nC = 35 x 10^-9 C
m = 3.5 micro gram = 3.5 x 10^-9 Kg
d = 35 cm = 0.35 m
(a) The electrostatic force between the two charges is balanced by the weight of another charge.
F = m g
(b) By substituting the values
Q2 = 13.34 x 10^-12 C
Q2 = 0.0134 nC
<span>The answer is:
PE lost every second = mgh = 1.2x10^6 * 9.81 * 50 = 5.89x10^8J
So, Power = 5.89x10^8W</span>
Answer:
The distance between two objects
Explanation:
Depending on how far away or how close two objects are will affect the gravity.
Answer:
Explanation:
Let the initial speed of the ball is given as
then angle of inclination is given as 33 degree
now its two components of velocity is given as
now the two positions with time given as
now when it hit the wall so we will have
now from above two equations we will have
now from above equations again