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Pie
3 years ago
9

How strong is the repulsive force exerted on two point charges that each carry 1.0 E-6 C of negative charge and are 0.30 meters

apart?
Coulomb's Constant is 9.0 E9 N*m2/C2

Remember to identity all of your data, write the equation, and show your work.
Physics
2 answers:
Brrunno [24]3 years ago
6 0

Answer:

Match the scenario to the type of movement that caused it.

Ted is in his home when a strong vibration occurs that shakes the dishes out of his cupboards.

Whitney feels a slight tremor three weeks subsequent to an earthquake in a nearby town.

Sam pulls off the side of a road after feeling the road move unexpectedly while driving to work.

Foreshock

Mainshock

Aftershock

Explanation: PLZZ HELP ME I NEED TO PASS STEM!

loris [4]3 years ago
3 0

Answer:

Explanation:

The repulsive Coulombic force

= Coulomb's Constant * Charge 1 * Charge 2 / distance^2

= 9.0E9 * 1.0E-6 * 1.0E-6 / 0.3^2

= 0.1 N

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An unknown substance from planet X has a density of 10 g/mL. It occupies a volume of 80 mL. What is the mass of this unknown sub
asambeis [7]

Answer:

800 mL

Explanation:

D*V=M

You pick out the numbers as well as what it is they represent from the word problem/explanation, then from there plug them in to the equations. Once you do that, you get your product and have the answer.

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5 0
3 years ago
A soccer ball is at rest. A player kicks the ball from the ground. What impact will the energy transfer have on the ball?
stepladder [879]

Answer:

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Explanation:

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A 5.0 m length of rope, with a mass of 0.52 kg, is pulled taut with a tension of 46 N. Find the speed of waves on the rope
aleksandrvk [35]

Answer:

Speed of waves on the rope is 21 m/s

Explanation:

Length of the rope (l) = 5.0 m

Mass of the rope (m) = 0.52 kg

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Formula of speed of waves on the rope:

\bold{v = \sqrt{\dfrac{T}{\mu}}}

\mu = Mass per unit length of the rope (m/l)

By substituting the values in the formula we get:

\implies  \rm v = \sqrt{\dfrac{T}{ \dfrac{m}{l} }} \\  \\  \implies  \rm v = \sqrt{\dfrac{Tl}{m}} \\  \\ \implies  \rm v =  \sqrt{ \dfrac{46 \times 5}{0.52} }  \\  \\ \implies  \rm v =  \sqrt{ \dfrac{230}{0.52} }  \\  \\ \implies  \rm v =  \sqrt{442.3}  \\  \\ \implies  \rm v = 21 \: m {s}^{ - 1}

Speed of waves on the rope (v) = 21 m/s

4 0
2 years ago
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3 years ago
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a

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