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Pie
3 years ago
9

How strong is the repulsive force exerted on two point charges that each carry 1.0 E-6 C of negative charge and are 0.30 meters

apart?
Coulomb's Constant is 9.0 E9 N*m2/C2

Remember to identity all of your data, write the equation, and show your work.
Physics
2 answers:
Brrunno [24]3 years ago
6 0

Answer:

Match the scenario to the type of movement that caused it.

Ted is in his home when a strong vibration occurs that shakes the dishes out of his cupboards.

Whitney feels a slight tremor three weeks subsequent to an earthquake in a nearby town.

Sam pulls off the side of a road after feeling the road move unexpectedly while driving to work.

Foreshock

Mainshock

Aftershock

Explanation: PLZZ HELP ME I NEED TO PASS STEM!

loris [4]3 years ago
3 0

Answer:

Explanation:

The repulsive Coulombic force

= Coulomb's Constant * Charge 1 * Charge 2 / distance^2

= 9.0E9 * 1.0E-6 * 1.0E-6 / 0.3^2

= 0.1 N

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A mole of water molecules would just about fill a
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Explanation:

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3 years ago
How do you graph distance and time for an object that moves at a constant speed?
LekaFEV [45]

Answer:

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v=\frac{\Delta s}{\Delta t}

On a distance-time graph, the distance is on the y-axis while the time is on the x-axis. The slope of the line is defined as:

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6 0
3 years ago
Read 2 more answers
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