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Pie
3 years ago
9

How strong is the repulsive force exerted on two point charges that each carry 1.0 E-6 C of negative charge and are 0.30 meters

apart?
Coulomb's Constant is 9.0 E9 N*m2/C2

Remember to identity all of your data, write the equation, and show your work.
Physics
2 answers:
Brrunno [24]3 years ago
6 0

Answer:

Match the scenario to the type of movement that caused it.

Ted is in his home when a strong vibration occurs that shakes the dishes out of his cupboards.

Whitney feels a slight tremor three weeks subsequent to an earthquake in a nearby town.

Sam pulls off the side of a road after feeling the road move unexpectedly while driving to work.

Foreshock

Mainshock

Aftershock

Explanation: PLZZ HELP ME I NEED TO PASS STEM!

loris [4]3 years ago
3 0

Answer:

Explanation:

The repulsive Coulombic force

= Coulomb's Constant * Charge 1 * Charge 2 / distance^2

= 9.0E9 * 1.0E-6 * 1.0E-6 / 0.3^2

= 0.1 N

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grigory [225]

Answer:h=160.84 W/m^2-K

Explanation:

Given

mass flow rate=0.3 kg/s

diameter of pipe=5 cm

length of pipe=10 m

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specific heat of vapor(c)=2190 J/kg.k

heat supplied Q=mc\Delta T=0.3\times 2190\times (30)

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Q=Q_{convection}

19,710=122.538 h

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<span>Since there is no friction, conservation of energy gives change in energy is zero Change in energy = 0 Change in KE + Change in PE = 0 1/2 x m x (vf^2 - vi^2) + m x g x (hf-hi) = 0 1/2 x (vf^2 - vi^2) + g x (hf-hi) = 0 (vf^2 - vi^2) = 2 x g x (hi - hf) Since it starts from rest vi = 0 Vf = squareroot of (2 x g x (hi - hf)) For h1, no hf Vf = squareroot of (2 x g x (hi - hf)) Vf = squareroot of (2 x 9.81 x 30) Vf = squareroot of 588.6 Vf = 24.26 For h2 Vf = squareroot of (2 x 9.81 x (30 – 12)) Vf = squareroot of (9.81 x 36) Vf = squareroot of 353.16 Vf = 18.79 For h3 Vf = squareroot of (2 x 9.81 x (30 – 20)) Vf = squareroot of (20 x 9.81) Vf = 18.79</span>
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