Given :
Temperature, T = 55° C = ( 55 + 273 ) K = 328 K .
Volume of container, V = 28.9 dm³ = 0.0289 m³ .
Pressure, P = 144 kPa = 144000 Pa .
To Find :
Number of moles of nitrogen gas.
Solution :
We know, by ideal gas equation :
PV = nRT ( R ( universal gas constant ) = 8.31 J K⁻¹ mol⁻¹ .

Therefore, number of moles of nitrogen gas is 1.53 moles.
Answer is: mass of water is 432 grams.
Chemical reaction: 2H₂ + O₂ → 2H₂O.
m(O₂) = 384 g.
M(O₂) = 2 · 16 g/mol = 32 g/mol, molar mass.
n(O₂) = m(O₂) ÷ M(O₂).
n(O₂) = 384 g ÷ 32 g/mol.
n(O₂) = 12 mol, amount of substance.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 12 mol · 2 = 24 mol.
m(H₂O) = n(H₂O) · M(H₂O).
m(H₂O) = 24 mol · 18 g/mol.
m(H₂O) = 432 g.
The density of the liquid is 0.884 g/mL.
<em>Density = mass/volume</em> = 22.1 g/25.0 mL = 0.884 g/mL