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2 years ago

Why is it that 85.48 rounded to two significant figures is 85 and not 86?

Chemistry

1 answer:

Gelneren [198K]2 years ago

8 0

Answer:

See below.

Explanation:

That is because of the .48.

85.48 is closer to 85 than 86.

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why do we heat the test tube in a glass beaker during a chemistry experiment and not directly over a flame?

bearhunter [10]

It is not directly over a flame because it depends on the substance you might not want to heat it too much.you never know what could happen

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3 years ago

Convert the following<br> 4. 100 cm =<br> 5. 453 m = _<br> 6. 89847nm = _<br> 7. 3Mm =

fredd [130]

4. I meter
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6. 89.84700 microns
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2 years ago

What characteristic of an element’s atoms always determines the element’s identity?

Anna11 [10]

Answer:

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Explanation:

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3 years ago

A block of aluminum with a mass of 140 g is cooled from 98.4°C to 62.2°C with a release of 4817 J of heat. From these data, calc

disa [49]

Answer:

specific heat = 0.951 j/g·°C

Explanation:

Heat flow equation => q = m·c·ΔT

q = heat flow = 4817 joules

m = mass in grams = 140 grams Aluminum

c = specific heat = ?

ΔT = Temperature Change in °C = 98.4°C - 62.2°C = 36.2°C

q = m·c·ΔT => c = q/m·ΔT = 4817j/(140g)(36.2°C) = 0.951 j/g·°C

6 0

2 years ago

The painkiller, Advil® contains the active ingredient ibuprofen (IB), which has a pKb of

denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

$Kb=\frac{[IBH^+][OH^-]}{[IB]}$

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

$pOH=14-8.20=5.80$

$[OH^-]=10^{-5.8}=1.585x10^{-6}M$

$Kb=10^{-5.20}=6.31x10^{-6}$

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

$6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}$

Finally, we solve for the equilibrium concentration of ibuprofen:

$[IB]=\frac{(1.585x10^{-6})(1.585x10^{-6})}{6.31x10^{-6}}=4.0x10^{-7}$

Learn more:

(Weak base equilibrium calculation) brainly.com/question/9426156

4 0

2 years ago