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Aleksandr [31]
3 years ago
12

Find the temperature at which ethanol boils on a day in the mountains when the barometric pressure is 537 mmhg. (The heat of vap

orization of ethanol is 39.3 kj/mol; the normal boiling point of ethanol is 78.3 degrees celcius, R=8.314 J/K mol.
Chemistry
1 answer:
Wittaler [7]3 years ago
7 0
Use the clausius clapeyron formula: 
<span>Ln (p1/p2) = (heat of vap) / (R = 8.314) [(1/t2)-(1/t1)] </span>
<span>Ln (p1/547)= (39300 j/mol) / (8.314) [(1/351.3 K) - (1/t1) </span>
<span>Ln (760/547) = (4726.97) [(2.85*10^-3) - (1/t1)] </span>
<span>760 mmhg = 1 atm!</span>
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See figure 1

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