Answer: 6.3x10-² moles of H20
Explanation: Solution:
Convert first the mass of O2 to moles which is 1 mole of O2 over its molar mass. The molar mass of O2 is 32. Then after that check the stoichiometric factors of both O2 and H2O.
0.252gO2 x 1mole O2/ 32 g O2 x 4 mol H2O/ 5 moles O2.
Both g of O2 and moles of O2 will be canceled out so the remaining unit is mole of H2O.
Answer:
Li
Explanation:
- In this case, "least exothermic" means that the correct answer is the least reactive of the alkali metals.
- The lower the ionization energy is, the higher the reactivity of the alkali metal is.
With the above information in mind, and remembering that ionization energy tends to decrease as we go down the group in the periodic table, the correct answer is Li, as it has the highest ionization energy among the alkali metals.
Answer:
17.57kg of
and its percentage yield is 81.0%
Explanation:
Through the reaction you can get the theoretical amount of
that must be produced.

If the amount obtained is less than the theoretical amount, it means that the initial sample was not 100% pure. Now the actual amount obtained is compared with the theoretical amount using a percentage
=81.0%
The specific heat means the heat absorbed when 1 g of the compound increase 1 ℃. So the specific heat is 41.71/(18.69*17)=0.131 J/(g*k).
Answer:
Como Representar la distribución electrónica por el método de la escalera y con los cajones de la distribución eléctronica: En "s" máximo 2 electrones En "p" máximo 6 electrones En "d" máximo 10 electrones
Explanation:
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