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Sergeu [11.5K]
3 years ago
7

Compare and contrast static, sliding, and rolling friction.

Physics
1 answer:
Mama L [17]3 years ago
4 0
Static friction - the friction that occurs when a force is being applied on a still object. 

Sliding friction - the friction that occurs upon a moving object; it is always lower than the static friction of the same object.

Rolling friction - the friction on a rolling object; it is actually a form of static friction with the contact point of the wheel with the surface.
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prohojiy [21]
The right answer is c. You are going to divide by the velocity or speed by time.
4 0
3 years ago
A student is bicycling north along Main Street to school. Another student is timing the bicycling student in order to determine
MatroZZZ [7]

The average velocity is -4.17 m/s

Explanation:

The average velocity of a body is given by:

v=\frac{d}{t}

where

d is the displacement of the body

t is the time elapsed

For the student in this problem, we have:

Initial position: x_i = 450 m

Final position: x_f = 200 m

So the displacement is

d=x_f -x_i = 200 - 450 = -250 m

The time elapsed is

t = 60 s

Therefore, the average velocity is

v=\frac{-250}{60}=-4.17 m/s

Where the negative sign means the student is moving towards the origin.

Learn more about average speed and velocity:

brainly.com/question/8893949

brainly.com/question/5063905

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8 0
4 years ago
Im need some help with this please
hram777 [196]
The answer is D, human.


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8 0
3 years ago
Which of the following are transferred or shared when two atoms react chemically? *
xxTIMURxx [149]

Answer:

One of the basic principles of chemistry is the electrostatic attraction between atoms or compounds. Electrons are on the outside of an atoms and that's where the charges come from and the interaction between those charges is what happens during a chemical bond. Therefore the answer would be electrons.

4 0
3 years ago
If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude
AveGali [126]

Answer: 1.5×10^10 N/C

Explanation:

E= F/q

Where E= magnitude of the electric field

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q= charge of the given body

Given F= 6.5×10^-8 N

q= 4.3× 10^-18 C

Therefore, E = 6.5×10 ^-8/ 4.3×10^-18

E = 1.5×10^10 N/C

7 0
3 years ago
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