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mart [117]
3 years ago
13

What is the molarity (M) of 1 liter of a solution that has 120 g of NaCl dissolved in it?

Chemistry
2 answers:
Ainat [17]3 years ago
4 0

Answer:

The answer to your question is 2.1

Explanation:

Data

Molarity = 1 l

mass = 120 g of NaCl

moles = ?

Formula

Molarity = \frac{number of moles}{Volume}

Process

1.- Calculate the number of moles of NaCl

Molecular weight NaCl = 23 + 35.5 = 58.5 g

2.- Calculate the number of moles using proportions

                           58.5 g of NaCl --------------- 1 mol

                        120.0 g of NaCl  ---------------  x

                             x = ( 120 x 1) / 58.5

                             x = 2.1 moles

3.- Calculate Molarity

Substitution

Molarity = \frac{2.1}{1}

Simplification and result

       Molarity = 2.1

Arada [10]3 years ago
3 0

Answer:

2.05 M

Explanation:

Molarity is defined as number of moles of solute in 1 L of solution.

Molarity = \frac{Number\ of\ moles\ of\ solute}{Volume\ of\ solution\ in\ L}

Here we have 120 g of NaCl in 1 liter of solution.

Molar mass of NaCl = 58.5 g

Number of moles of NaCl = \frac{Given\ mass\ of\ solute}{Molar\ mass\ of\ solute} = \frac{120}{58.5}=2.05\ moles

Volume of solution = 1 L

Molarity = \frac{Number\ of\ moles\ of\ solute}{Volume\ of\ solution\ in\ L}=\frac{2.05}{1}=2.05\ moles\ per\ litre

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Answer is 3.306 Pa.


<em>Explanation:</em>


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