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3 years ago

Which laws can be combined to form the ideal gas law?

2 answers:

5 0

<h2><u><em>Answer:</em></u><em> Charles's law, Avogadro's law and Boyle's law.</em></h2><h2><em></em></h2><h2><em>Charles law states the constant ratio of volume to temperature, at constant pressure. Boyle's law states the constat product of pressure and volumen at constant temperature. Avogadro's law states that equal volumes of gases at the same temperature and pressure have equal number of particles.</em></h2><h2><em></em></h2><h2><em>So, all those three laws combined state the relation of pressure, volume, temperature and number of particles of a gas, which is what the ideal gas law does: PV = n RT.</em></h2>

Aleksandr [31]3 years ago

4 0

Answer:

charles' law ,Avogadro law and boyles law

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Na podstawie położenia w u.o. oraz liczb A i Z:

Dvinal [7]

Ok A is the correct answer

5 0

3 years ago

Read 2 more answers

Which type of change does the statement describe? Someone help fast

grandymaker [24]

Explanation:

bottom right = physical change

top left = chemical change

top right = physical change

bottom left = chemical change

<h3>A physical change is a change that goes from one form to another and physical changes can be reversed</h3><h3>example: water to ice or air to water</h3><h3 /><h3>A chemical change is when a substance combines with another substance and when it is combined it cannot be reversed</h3><h3>example: burning and or rusting</h3>

7 0

3 years ago

When the experiment was carried out, the temperature was 22 oC and atmospheric pressure was 1.007 atm. Using the Ideal Gas Law a

lesantik [10]

Answer:

number of moles of $H_2$ =4.16mol

Explanation:

experiment data:

temperature= $22^{\circ}C$ =273+22 k=295k

pressure=1.007 atm

volume is missing so assuming volume-=100L

using ideal law relationship

ideal gas means gas which occupies negligible space and there is no interaction between the molecules of gases.

PV=nRT

put all the experimental data, we get

n=4.15 mol

number of moles of $H_2$ =4.16mol

4 0

3 years ago

A sealed 1.0 L flask is charged with 0.500 mol of I2 and 0.500 mol of Br2. An equilibrium reaction ensues: I2 (g) + Br2 (g) ↔ 2I

Daniel [21]

Answer: Thus the value of $K_{eq}$ is 110.25

Explanation:

Initial moles of $I_2$ = 0.500 mole

Initial moles of $Br_2$ = 0.500 mole

Volume of container = 1 L

Initial concentration of $I_2=\frac{moles}{volume}=\frac{0.500moles}{1L}=0.500M$

Initial concentration of $Br_2=\frac{moles}{volume}=\frac{0.500moles}{1L}=0.500M$

equilibrium concentration of $IBr=\frac{moles}{volume}=\frac{0.84mole}{1L}=0.84M$ [/tex]

The given balanced equilibrium reaction is,

$I_2(g)+Br_2(g)\rightleftharpoons 2IBr(g)$

Initial conc. 0.500 M 0.500 M 0 M

At eqm. conc. (0.500-x) M (0.500-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[IBr]^2}{[Br_2]\times [I_2]}$

$K_c=\frac{(2x)^2}{(0.500-x)\times (0.500-x)}$

we are given : 2x = 0.84 M

x= 0.42

Now put all the given values in this expression, we get :

$K_c=\frac{(0.84)^2}{(0.500-0.42)\times (0.500-0.42)}$

$K_c=110.25$

Thus the value of the equilibrium constant is 110.25

8 0

3 years ago

One gram of glass will rise 20° C when------------calories of heat are applied

astra-53 [7]

Answer:

3.2 Calories

Explanation:

Here we will use a formula

Heat added in calories = Mass of glass x Increase in temperature x specific heat of glass

As we know that, specific heat is the amount of energy required to raise the temperature of one gram of any substance by 1°C. It has a constant value for every substance and for glass the specific heat is .16 calories/gm

Incorporating the values of mass (m), temperature(T) and specific heat (c) in formula.

calories (small calories) = l.0 g x 20 degrees x .16 calories/gm/°C

= 3.2 calories

Hope it helps:)

6 0

3 years ago