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andreyandreev [35.5K]
3 years ago
14

Assuming that the concentration of sodium hypochlorite is 4.0% (w/v), calculate the molarity of the sodium hypochlorite solution

. molar mass of sodium hypochlorite = 74.44g/mol.
Chemistry
1 answer:
levacccp [35]3 years ago
5 0
We are told that the concentration of sodium hypochlorite is 4.0% (w/v). To calculate the molarity of the sodium hypochlorite solution, let us consider a sample volume of 0.1 liter. Since we are given a w/v (Percent of weight of solution in the total volume of solution) value, it means that there are 4 <span>grams of sodium hypochlorite per 100 mL of solution (0.1 liter). Molarity is measured in moles per liter. So we'll just convert the given 4 grams to moles using the molar mass.
</span><span>
4 grams</span>sodium hypochlorite * (1 mol sodium hypochlorite/ 74.44 g sodium hypochlorite) = 0.054 moles sodium hypochlorite

So we have 0.054 moles sodium hypochlorite  / 0.1 L solution
<span>
Thus the molarity is 0.53 mol/L or just 0.53 M.


</span>
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The density of thorium, which has the FCC structure, is 11.72 g/cm3. The atomic weight of thorium is 232 g/mol. Calculate (a) th
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(a) a = 5.08x10⁻⁸ cm

(b) r = 179.6 pm  

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(a) The lattice parameter "a" can be calculated using the following equation:

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<em>where ρ: is the density of Th = 11.72 g/cm³, N° atoms/cell = 4, m: is the atomic weight of Th = 232 g/mol, Vc: is the unit cell volume = a³, and </em>N_{A}<em>: is the Avogadro constant = 6.023x10²³ atoms/mol. </em>

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<em>where r: is the atomic radius of Th</em>

Hence, the atomic radius of Th is:

r = \frac{a*\sqrt{2}}{4} = \frac{5.08 \cdot 10^{-8} cm*\sqrt{2}}{4} = 1.796 \cdot 10^{-8} cm = 179.6 pm    

I hope it helps you!    

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3 years ago
Read 2 more answers
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