What is the legal limit?
The lowest concentration that can officially be reported for any constituent in drinking water is known as the "Legal Limit".
Contamination of water:
The level that safeguards human health and that water systems can attain with the finest technology is reflected in the regulatory limit for a contaminant.
<u><em>How does it occur:</em></u>
- Plumbing components are the main way that lead and copper enters the drinking water. The health effects of lead and copper exposure can range from brain damage to stomach discomfort.
- Nitrogen, bleach, salts, pesticides, metals, bacterial toxins, and human or animal medications are examples of chemical pollutants. Organisms in the water are biological pollutants. Other names for them include microorganisms and microbiological pollutants.
In order to control corrosion, the system must take a variety of additional measures if lead concentrations reach an action threshold of 15 ppb or copper concentrations exceed an action level of 1.3 ppm in more than 10% of measured customer taps.
Learn more about the contamination of water here,
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It’s the second answer. “it gets used for metabolic process & released as heat” i think.
I think its because its more accurate because it shows you the numbers rather than you reading the approximate temperature on a liquid thermometer
<span> ester of Ethanol and Ethanoic Acid is Ethyl Ethanoate. </span>
<span><span><span><span><span><span><span><span>C</span></span></span><span><span><span>2</span></span></span></span><span><span><span><span>H</span></span></span><span><span><span>5</span></span></span></span><span><span>O</span></span><span><span>H</span></span><span><span>(</span></span><span><span>l</span></span><span><span>)</span></span><span><span>+</span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>3</span></span></span></span><span><span>C</span></span><span><span>O</span></span><span><span>O</span></span><span><span>H</span></span><span><span>(</span></span><span><span>l</span></span><span><span>)</span></span><span><span><span><span><span><span><span><span><span>c</span></span><span><span>o</span></span><span><span>n</span></span><span><span>c</span></span><span><span>.</span></span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>S</span></span><span><span><span><span>O</span></span></span><span><span><span>4</span></span></span></span><span><span><span><span>/</span></span></span></span><span><span>w</span></span><span><span>a</span></span><span><span>r</span></span><span><span>m</span></span></span></span><span /></span></span></span><span><span><span><span>−</span><span>−−−−−−−−−−</span><span>→</span></span></span></span></span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>3</span></span></span></span><span><span>C</span></span><span><span>O</span></span><span><span>O</span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>3</span></span></span></span><span><span>(</span></span><span><span>a</span></span><span><span>q</span></span><span><span>)</span></span><span><span>+</span></span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>O</span></span><span><span>(</span></span><span><span>l</span></span><span><span>)</span></span></span></span><span>C2H5OH(l)+CH3COOH(l)→conc.H2SO4/warmCH3COOCH2CH3(aq)+H2O(l)</span></span></span>
<span><span><span><span><span><span>Condition: Warm con. reactants with conc.</span></span></span></span><span>Condition: Warm con. reactants with conc.</span></span></span><span><span><span><span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>S</span></span><span><span><span><span>O</span></span></span><span><span><span>4</span></span></span></span></span></span><span>H2SO4</span></span></span>
Answer:
ΔH⁰(11.4g NH₄NO₃) = -30.59Kj (4 sig. figs. ~mass of NH₄NO₃(s) given) (exothermic)
Explanation:
3NH₄NO₃(s) + C₁₀H₂₂(l) + 14O₂(g) => 3N₂(g) + 17H₂O(g) + 10CO₂(g)
ΔH⁰(f): 3(-365.6)Kj 1(-301)Kj 14(0)Kj 3(0)Kj 17(-241.8)Kj 10(-393.5)Kj
= -1096.8Kj = -301Kj = 0Kj = 0Kj = -4110.6Kj = -3930.5Kj
ΔHₙ°(rxn) = ∑
(ΔH˚(f)products) - ∑(ΔH˚(f)reactants)
= [3(0)Kj + 17(-241.8)Kj + (-393.5)Kj] - [(-(1096.8)Kj + (-301)Kj + (0)Kj]
= [-(8041.1) - (-1397.8)]Kj
= -6643.3Kj (for 3 moles NH₄NO₃ used in above equation)
∴ Standard Heat of Rxn = -6643.3Kj/3moles = -214.8Kj/mole NH₄NO₃(s)
ΔH°(rxn for 14.11g NH₄NO₃(s)) = (11.4g/80.04g·mol⁻¹)(-214.8Kj/mol) = 30.5937Kj ≅ 30.59Kj (4 sig. figs. ~mass of NH₄NO₃(s) given)