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velikii [3]
3 years ago
9

Who gains altitude more quickly, a pilot traveling 400 mph and rising at an angle of 30°, or a pilot traveling 300 mph and risin

g at an angle of 40°, ?( Type "x" before the correct statement.) ________ The pilot raising 30° at 400 mph. _________ The pilot raising 40° at 300 mph. Now enter how much more quickly (to the nearest whole mph) does he gain altitude?
Physics
1 answer:
Basile [38]3 years ago
4 0
The rate of altitude increase is equivalent to the vertical component of the pilot's velocity. Let the first pilot's velocity be A and the second's be B.
Ay = Asin(∅)
Ay = 400sin(30)
Ay = 200 mph

By = Bsin(∅) 
By = 300sin(40)
By = 192.8 mph

200 - 192.8 = 7.2 mph
The first pilot gains altitude faster by 7.2 mph than the second pilot.
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Estimate the peak wavelength for radiation from ice at 273 k.
Andrews [41]
<h2>Answer: 10615 nm</h2>

Explanation:

This problem can be solved by the Wien's displacement law, which relates the wavelength  \lambda_{p} where the intensity of the radiation is maximum (also called peak wavelength) with the temperature T of the black body.

In other words:

<em>There is an inverse relationship between the wavelength at which the emission peak of a blackbody occurs and its temperature.</em>

Being this expresed as:

\lambda_{p}.T=C    (1)

Where:

T is in Kelvin (K)

\lambda_{p} is the <u>wavelength of the emission peak</u> in meters (m).

C is the <u>Wien constant</u>, whose value is 2.898(10)^{-3}m.K

From this we can deduce that the higher the black body temperature, the shorter the maximum wavelength of emission will be.

Now, let's apply equation (1), finding \lambda_{p}:

\lambda_{p}=\frac{C}{T}   (2)

\lambda_{p}=\frac{2.898(10)^{-3}m.K}{273K}  

Finally:

\lambda_{p}=10615(10)^{-9}m=10615nm  This is the peak wavelength for radiation from ice at 273 K, and corresponds to the<u> infrared.</u>

8 0
3 years ago
Which statement about the properties of matter is true? *25*
mojhsa [17]

Answer:

A possible answer would be that chemical properties depend on phisical properties if and if only the phisical properties depend on the chemical ones ( see the laws of thermodinamics)

3 0
3 years ago
What is the symbol name?
murzikaleks [220]

Answer:

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Explanation:

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hope this helps, take care and stay safe

7 0
3 years ago
a water-balloon launcher with mass 4 kg fires a 0.5 kg balloon with a velocity of 3 m/s to the east. what is the recoil velocity
kotykmax [81]
I think we will use the law of conservation of linear momentum;
M1V1 = M2V2
M1 =  4 kg (mass of the water balloon launcher)
V1=?
M2= 0.5 kg ( mass of the balloon)
V2 = 3 m/s

Therefore; 4 V1 = 0.5 × 3
                   4V1= 1.5
                     V1= 1.5/4
                          = 0.375 m/s










5 0
3 years ago
Read 2 more answers
large truck exerts 7000 n of force on a piston with an area of 0.4m squared and the is ton can only support 16,000 pa of pressur
sasho [114]
7000 N / 0,4m^2  = 17 500 Pa.
6 0
3 years ago
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