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Tems11 [23]
2 years ago
13

I need help ASAP

Physics
2 answers:
Blizzard [7]2 years ago
6 0

Answer:

(a). forms.

Explanation:

Bro even i ain't sure.

hodyreva [135]2 years ago
4 0

Answer:

I think its A? Because in the water cycle it goes from a liquid to a gas?

Explanation:

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The relationship between electrical and charge force is that electrical force strengthens and increases the energy pulses and reflects off an object and makes the force about two times greater with charge.
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A lens of focal length 10.0 cm
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30cm

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One solution to minimize resonance with buildings is to ______ the width to span ratio.
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Increase

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Resonance is a phenomenon which occurs when a body A in motion set another body B into motion of it own natural frequency. So for resonance to be minimize in a body is to increase the width to span ratio. So as to reduce the overall vibration which affects directly building resonance, the stiffness or trusses and girders should be increase. The increase in this aspect helps to reinforce building structure and support.

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The water cycle was described in the Scriptures long before modern scientists understood it.
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False

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4 0
2 years ago
Read 2 more answers
A(n) 1400-kg car going at 6.32 m/s in the positive x direction collides with a 2900-kg truck at rest. The collision is totally i
tresset_1 [31]

Answer:

a) Acceleration of the car is given as

a_{car} = -21 m/s^2

b) Acceleration of the truck is given as

a_{truck} = 10.15 m/s^2

Explanation:

As we know that there is no external force in the direction of motion of truck and car

So here we can say that the momentum of the system before and after collision must be conserved

So here we will have

m_1v_1 + m_2v_2 = (m_1 + m_2)v

now we have

1400 (6.32) + 2900(0) = (1400 + 2900) v

v = 2.06 m/s

a) For acceleration of car we know that it is rate of change in velocity of car

so we have

a_{car} = \frac{v_f - v_i}{t}

a_{car} = \frac{2.06 - 6.32}{0.203}

a_{car} = -21 m/s^2

b) For acceleration of truck we will find the rate of change in velocity of the truck

so we have

a_{truck} = \frac{v_f - v_i}{t}

a_{truck} = \frac{2.06 - 0}{0.203}

a_{truck} = 10.15 m/s^2

5 0
2 years ago
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