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Complete Question
An airplane takes off a runway at a constant speed of 49 m/s at constant angle 30 to the horizontal.How high (in meters ) is the airplane above the ground 13 seconds after takeoff?
Answer:
The height is
Explanation:
From the question we are told that
The speed at which the plane takes off is
The angle at which it takes off is
The time taken is
The vertical distance traveled is mathematically represented as
Substituting values
Initial velocity (Vi) = 25 m/s
acceleration (a) =
time interval (t) = 5 sec
let us assume that final velocity after 5 sec be Vf
As acceleration is constant, we can apply the the equation of motion with constant acceleration i.e.
Hence,
so, the velocity of bicyclist will be 5 m/s after 5 sec