Boiling water. <span>heat goes from the burner into the pot which heats the water at the bottom. this hot water rises and cooler water moves down to replace it, causing a circular motion.</span>
It’s to push an object in it’s direction of where it’s leading to.
Answer:
Explanation:
Given that,
Hot reservoir temperature is
TH = 58°C
TH = 58 + 273 = 331 K
Cold reservoir temperature
TC = -17°C
TC = -17°C + 273 = 256K
In 24minutes 590 J of heat was removed from hot reservoir
t = 24mins
t = 24 × 60 = 1440 seconds
Then,
Power is given as
P = E / t
P = 590 / 1440
P = 0.41 W
Since this removed from the hot reservoir, then, QH = 0.41W
We want to find heat expelled to the cold reservoir QX
Efficiency is given as
η = 1 - TH/TC = 1 - QH/QC
1 - TH/TC = 1 - QH/QC
TH/TC = QH/QC
Make QC subject of formula
QC = QH × TC / TH
QC = 0.41 × 256 / 331
QC = 0.317 W
Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :
F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
