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Serjik [45]
4 years ago
14

Explain haw fluctuations in abiotic can influence populations?

Chemistry
1 answer:
aleksandr82 [10.1K]4 years ago
3 0
The fluctuations in abiotic cycles can influence the population in many ways. The population of a particular area depends on the various abiotic cycles such as nitrogen cycle, carbon cycle, phosphorous cycle. The changes in these cycles affects the life of population. Fluctuation results in hibernation of species. Some of the organisms migrate to another place in search of normal environment. The early breeding results in creating problems. It disturbs the ecological balance by using the limited supply of resources. The fluctuation in phosphorous cycle can affect the aquatic population. As the dependency of population on abiotic cycles is as important as the biotic factors the fluctuations can cause many problem.

If my answer was help full please mark as ♚☻
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The protein catalase catalyzes the reaction The Malcolm Baldrige National Quality Award aims to:
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The question is missing a part, so the complete question is as follows:

The protein catalase catalyzes the reaction The Malcolm Bladrigde National Quality Awards aims to: 2H2O2 (aq) ⟶ 2H2O (l) + O2 (g) and has a Michaelis-Menten constant of KM = 25mM and a turnover number of 4.0 × 10 7 s -1. The total enzyme concentration is 0.012 μM and the intial substrate concentration is 5.14 μM. Catalase has a single active site. Calculate the value of Rmax (often written as Vmax) for this enzyme. Calculate the initial rate, R (often written as V0), of this reaction.

1) Calculate Rmax

The turnover number (Kcat) is a ratio of how many molecules of substrate can be converted into product per catalytic site of a given concentration of enzyme per unit of time:

Kcat = \frac{Vmax}{Et},

where:

Vmax is maximum rate of reaction when all the enzyme sites are saturated with substrate

Et is total enzyme concentration or concentration of total enzyme catalytic sites.

Calculating:

Kcat = \frac{Vmax}{Et}

Vmax = Kcat · Et

Vmax = 4×10^{7} · 1.2 × 10^{-8}

Vmax = 4.8 × 10^{-1} M

2) Calculate the initial rate of this reaction (R):

The Michaelis-Menten equation studies the dynamics of an enzymatic reaction. This model can explain how an enzyme enhances the rate of a reaction and how the reaction rate depends on the concentration of the enzyme and its substrate. The equation is:

V0 = \frac{[S].(Vmax)}{KM + [S]}, where:

[S] is the substrate's concentration

KM is the Michaelis-Menten constant

Substituting [S] = 5.14 × 10^{-6}, KM = 2.5 × 10^{-4} and Vmax = 4.8 × 10^{-1}, the result is V0 = 0.478 M.

The answers are Vmax = 4.8 × 10^{-1} M and V0 = 0.478 M.

 

7 0
4 years ago
What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

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Gas is real at ? plz ans
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Low pressure and high temperature
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