At equivalence there is no more HA and no more NaOH, for this particular reaction. So that means we have a beaker of NaA and H2O. The H2O contributes 1 x 10-7 M hydrogen ion and hydroxide ion. But NaA is completely soluble because group 1 ion compounds are always soluble. So NaA breaks apart in water and it just so happens to be in water. So now NaA is broken up. The Na+ doesn't change the pH but the A- does change the pH. Remember that the A anion is from a weak acid. That means it will easily attract a hydrogen ion if one is available. What do you know? The A anion is in a beaker of H+ ions! So the A- will attract H+ and become HA. When this happens, it leaves OH-, creating a basic solution, as shown below.
Answer:
Explanation:
Data provided as per the question below:-
Wavelength = 430.nm
The computation of the frequency of the light is shown below:-
Frequency = Velocity of light ÷ Wavelength
The Velocity of light = 
Wavelength = 430 nm = 
m
Frequency = 
=
Therefore for determining the frequency we simply applied the above formula.
Answer:
The answers to your question are below
Explanation:
a) 6.85×1020 H2O2 molecules
H2O2 MW = 32 + 2 = 34 g
34g -------------------- 6.023 x 10²³ molecules
x ------------------- 6.85 x 10 ²⁰
x = (6.85 x 10 ²⁰)(34)/ 6.023 x 10²³
x = 0.038 g
3.3×1022 SO2 molecules
MW SO2 = 32 + 32 = 64g
64 g -------------------- 6.023 x 10²³ molecules
x -------------------- 3.3×1022 SO2 molecules
x = (3.3×1022 SO2)(64) / 6.023 x 10²³
x = 3.51 g
5.5×1025 O3 molecules
MW = 16 x 3 = 48g
48 g ----------------- 6.023 x 10²³ molecules
x ------------------ 5.5×1025 O3 molecules
x = (5.5×1025 )(48) / 6.023 x 10²³
x = 4383 g
9.30×1019 CH4 molecules
MW = 12 + 4 = 16 g
16 g -------------------- 6.023 x 10²³ molecules
x -------------------- 9.30×1019 CH4 molecules
x = (9.30×1019)(16) / 6.023 x 10²³
x = 0.0025 g
Answer:
2.81 × 10⁶ mm³
2.81 × 10⁻³ m³
Explanation:
Step 1: Given data
Length (l): 250 mm
Width (w): 225 mm
Thickness (t): 50 mm
Step 2: Calculate the volume of the textbook
The book is a cuboid so we can find its volume (V) using the following expression.
V = l × w × t = 250 mm × 225 mm × 50 mm = 2.81 × 10⁶ mm³
Step 3: Convert the volume to cubic meters
We will use the relationship 1 m³ = 10⁹ mm³.
2.81 × 10⁶ mm³ × 1 m³ / 10⁹ mm³ = 2.81 × 10⁻³ m³
