Let x be the volume of fluid removed and the volume of pure antifreeze that is added. The concentration of antifreeze in the fluid is 0.3, the concentration in pure antifreeze is 1 and that in the final solution is 0.4 The volume of the final solution is 10.
(10 - x)(0.3) + x = 10(0.4)
0.3 + 0.7x = 0.4
x = 1/7 quarts
The volume that should be drained is 1/7 quarts
To find the neutrons you add the mass number and the atomic number for neutrons
Hope this helps
-Zayn Malik
well, tell maggie i said hello...and tell fred that he still owes me money from last weeks poker match.....and make sure flourence knows that everything is gonna be ok with his toe problems......thanks
