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3 years ago

What is khasra record? What it tells?

Chemistry

2 answers:

AnnZ [28]3 years ago

8 0

Answer:

The Khasra record of the Patwari gives information regarding the map of land. It identifies which plot of land is owned by whom.

Explanation:

Andreas93 [3]3 years ago

6 0

Answer:

Khasra is a register of land records maintained by the Patwari. It contains the details of the crops grown and the harvest inspections done by the Patwari in the village.

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If measurements of a gas are 100L and 300 kilopascals and then the gas is measured a second time and found to be 75L, describe w

Tanya [424]

Answer:

The pressure of the gas increased (if temperature remained constant).

The Boyle's law supports this observation.

Explanation:

The initial measurements of the gas are given as;

volume = 100 L

Pressure = 300 kpa

The second measurement is given as;

Volume = 75 L

The second reading implies that the volume of the gas has decreased. If the temperature of the gas remained constant, then the pressure must have increased according to the Boyle's law;

At constant temperature, the pressure of a given mass of an ideal gas is inversely proportional to its volume.

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3 years ago

Give a reason why laboratory apparatus are made of ceramics

mixer [17]

Ofc porcelain crucible is a high efficiency material and It can be used as a test piece, retort, but the most common use is as a smelting vessel which is used in furnaces or fire with direct flame.

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3 years ago

For the following reaction, 4.53 grams of calcium hydroxide are mixed with excess sulfuric acid. The reaction yields 6.75 grams

vagabundo [1.1K]

Answer:

$\large \boxed{\text{8.32 g; 81.1 \%}}}$

Explanation:

MM: 74.09 136.14

H₂SO₄ + Ca(OH)₂ ⟶ CaSO₄ + 2H₂O

m/g: 4.53

1. Theoretical yield

(a) Moles of Ca(OH)₂

$\text{Moles of Ca(OH)${_2}$} = \text{4.53 g Ca(OH)${_2}$} \times \dfrac{\text{1 mol Ca(OH)${_2}$}}{\text{74.09 g Ca(OH)${_2}$}} = \text{0.161 14 mol Ca(OH)${_2}$}$

(b) Moles of CaSO₄

$\text{Moles of NH${_3}$} = \text{0.061 14 mol Ca(OH)${_2}$} \times \dfrac{\text{1 mol CaSO${_4}$}}{\text{1 mol Ca(OH)${_2}$}} = \text{0.061 14 mol CaSO${_4}$}$

(c) Theoretical yield

$\text{Mass of CaSO${_4}$} = \text{0.061 14 mol CaSO${_4}$} \times \dfrac{\text{136.14 g CaSO${_4}$}}{\text{1 mol CaSO${_4}$}} = \textbf{8.32 g CaSO${_4}$}$

2. Percent yield

$\text{Percent yield} = \dfrac{\text{ actual yield}}{\text{ theoretical yield}} \times 100 \% = \dfrac{\text{6.75 g}}{\text{8.32 g}} \times 100 \, \% = \text{81.1 \%}$

$\text{The percent yield is } \large \boxed{\textbf{81.1 \%}}}$

4 0

3 years ago

What is a niche? (Select all that apply.)

Alekssandra [29.7K]

Answer: I'm pretty sure it's D

Explanation :I hope

3 0

2 years ago

A liquid has an empirical formula CCl2, and a boiling point of 1 21 oC. When vapourised, the gaseous compound has a density of 4

Darya [45]

Based on the data given, the molar mass of the gas is 165.5 g/mol while the molecular weight of the gas is 165.5 amu

<h3>How can molar mass of a gas be obtained from density, temperature and pressure?</h3>

The molar mass of a gas can be obtained from density, temperature and pressure using the formula below:

molar mass = density × molar gas constant × temperature/pressure

Molar gas constant, R = R = 0.082 L.atm/mol/K.

Temperature = 150 °C = 423 K

Pressure = 785 torr = 1.033 atm

density = 4.93 g/L

molar mass of gas = 4.93 × 0.082 × 423/1.033

molar mass of gas = 165.5 g/mol

Then, molecular weight of the gas = 165.5 amu

Therefore, the molar mass of the gas is 165.5 g/mol while the molecular weight of the gas is 165.5 amu

Learn more about molar mass of a gas at: brainly.com/question/26215522

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2 years ago