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pogonyaev
2 years ago
7

Speed-48km time-5hour​

Chemistry
1 answer:
Rom4ik [11]2 years ago
7 0

Answer:

Whats the question?

Explanation:

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What happens in a reduction?
MatroZZZ [7]

Answer:

A. An element gains one or more electrons

Explanation:

Reduction is a chemical reaction that involves the gaining of electrons by one of the atoms involved in the reaction between two chemicals. The term refers to the element that

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3 years ago
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Which TWO are most likely to form a compound?<br> C<br> Mg<br> S<br> Ar
lbvjy [14]
Answer is Mr and S as MgS ..
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At an elevated temperature, Kp=4.2 x 10^-9 for the reaction 2HBr (g)---&gt; +H2(g) + Br2 (g). If the initial partial pressures o
Damm [24]

Answer : The partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

Explanation :

The partial pressure of HBr = 1.0\times 10^{-2}atm

The partial pressure of H_2 = 2.0\times 10^{-4}atm

The partial pressure of Br_2 = 2.0\times 10^{-4}atm

K_p=4.2\times 10^{-9}

The balanced equilibrium reaction is,

                                2HBr(g)\rightleftharpoons H_2(g)+Br_2(g)

Initial pressure    1.0×10⁻²       2.0×10⁻⁴      2.0×10⁻⁴

At eqm.            (1.0×10⁻²-2p)   (2.0×10⁻⁴+p)  (2.0×10⁻⁴+p)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{H_2})(p_{Br_2})}{(p_{HBr})^2}

Now put all the values in this expression, we get :

4.2\times 10^{-9}=\frac{(2.0\times 10^{-4}+p)(2.0\times 10^{-4}+p)}{(1.0\times 10^{-2}-2p)^2}

p=-1.99\times 10^{-4}

The partial pressure of H_2 at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶

Therefore, the partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

4 0
3 years ago
According to Hess’s law, if a series of intermediate reactions are combined, the enthalpy change of the overall reaction is
sdas [7]
I think the answer is B. the sum of the enthalpy changes of the intermidiate reactions
4 0
3 years ago
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The radioactive atom R 88 210 a is an alpha emitter. What nucleus does it produce?
olasank [31]

Answer:

X 86 206

Explanation:

Radioactive atoms are nuclei that can under go disintegration to emit either an alpha particle, beta particle or gamma radiation. The process could be spontaneous or stimulated.

When a radioactive atom R 88 210 emits alpha particle, it would produce an element with atomic number 86 and mass number 206 i.e X 86 206. An alpha particle is usually a helium nucleus.

                     R^{210} ⇒ x^{206} + He^{4} + energy

5 0
2 years ago
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