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stepladder [879]
3 years ago
9

The position of a 50 g oscillating mass is given by x(t)=(2.0cm)cos(10t−π/4), where t is in s. If necessary, round your answers

to three significant figures. Determine:
the amplitude
2cm
the period
.628s
the spring constant
5N/m
the phase constant
-.785rad
the initial coordinate of the mass
1.41cm
the initial velocity
14.1 cm/s
maximum speed 20 cm/s
what's the total energy?
Physics
1 answer:
Leona [35]3 years ago
5 0
For the answer to the question above, this is the maximum displacement, the spring has only elastic potential energy.
spring is constant @ 5 N/m
maximum displacement = 2 cm = 0.02 m
elastic potential energy = 1/2 kx²
= 0.5 x 5 x 0.02²
So the answer would be
= 0.001 Joules
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The mass of an object is a measure of its
valentina_108 [34]
Hope it helped you.

A. Acceleration is a wrong answer. Acceleration is the rate of change to in velocity. It involves a change in speed and direction. 

B.  Force is a wrong answer. Force is a directions from push/or pull.

C. Inertia is a correct. Inertia is a tendency of an object to stay at the rest or preserve its state of motion.

D. Velocity is a incorrect answer. Velocity is the placement of an object during a specific unit of time. It has two measurements are needed to determine velocity.

-Charlie

-Thank you so much!

Have a great day!
4 0
3 years ago
A mass on a spring vibrates in simple harmonic motion at an amplitude of 8.0 cm. If the mass of the object is 0.20 kg and the sp
Dmitry [639]

Answer:

Frequency, f = 3.73Hz

Explanation:

The frequency of a simple harmonic 6is given by:

f = w/2pi

But w= Sqrt( k/m)

Where k is the spring constant

And m is the mass

Given:

Mass=0.20kg

Spring constant, k=130N/m

w= Sqrt(130/0.20)

w= Sqrt(650)

w= 25.50 m

Frequency, f = w/2pi

f = 25.50/(2×3.142)

f = 3.73Hz

5 0
3 years ago
A fuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predete
zmey [24]

Answer:

The diameter of wire should be 4.04 \times 10^{-4} m

Explanation:

Given:

Current density J = 500 \times 10^{4} \frac{A}{m^{2} }

Current I = 0.64 A

From the formula of current density,

  J = \frac{I}{A}

Where A = area of cylindrical wire = \pi r^{2}

  \pi r^{2} = \frac{I}{J}

  r^{2} = \frac{I}{\pi J }

   r = \sqrt{\frac{0.64}{3.14 \times 500 \times 10^{4} } }

   r = 2.02 \times 10^{-4}m

For finding the diameter of wire,

   d = 2r

   d = 4.04 \times 10^{-4}m

Therefore, the diameter of wire should be 4.04 \times 10^{-4} m

8 0
3 years ago
A person who weighs 864 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally
svetoff [14.1K]

Answer:

A=60.06 x 10⁻⁵ m²

Explanation:

Given that

Weight of the person = 864 N

Weight of the bike = 85 N

The total weight ,car + bike ,Wt= 864 + 85 N

 Wt = 949 N

2 p = 949 N

The weight on the each tire(F) = 474.5  N

P = 7.9 x 10 ⁵  Pa

We know that

Force = Pressure x Area

F= P A

By putting the values

474.5 =  7.9 x 10 ⁵  A

A=60.06 x 10⁻⁵ m²

Therefore area of contact A

A=60.06 x 10⁻⁵ m²

4 0
3 years ago
51. A balloon starts rising from the ground, vertically upwards, uniformly at the rate of 1 m s-1. At the end of 4 seconds, a bo
strojnjashka [21]

Answer:

4s

Explanation:

when a bOdy rises into the air,the time it takes to reach a particular height is the same as the time it will take the body to fall from that height to the ground.

5 0
1 year ago
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