Question

If a object accelerates from rest, what will its velocity be after 12.3s if it has a constant acceleration of 4.6m/S2

Answer 1

As per the question, the initial velocity of a object[u] = 0

The acceleration of the object  $[a]=4.6\ m/s^2$

The time [t] = 12.3 s

We are asked to calculate the velocity of the object at that time.

From equation of kinematics we know that-

                         V = u+at   [Where v is the final velocity of the particle]

                             =0+4.6*12.3 m/s

                             =56.58 m/s       [ans]